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3 years ago

Let x define the position of an object such that x =

Physics

1 answer:

timama [110]3 years ago

7 0

See the attached picture for answers

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What is the total resistance of a 3-ohm resistor and a 6-ohm resistor in parallel?

Fittoniya [83]

1/R=1/3+1/6
1/R=2/6+1/6=3/6
R=6/3=2ohms
Total R=2ohms

5 0

3 years ago

How can you determine the diameter of water

katrin [286]

Answer:

To test your hydraulic skills, your Boss has requested you calculate the difference in water surface elevation between two reservoirs that are connected.

Explanation:

8 0

3 years ago

Under what conditions the reaction rate of an enzymolysis that follows Michaelis-Menten kinetics is a quarter of its maximum val

ExtremeBDS [4]

Solution :

Michaelis-Menten kinetics in the field of biochemistry is considered as one of the well known models for enzyme kinetics. The model represents an equation that describes the enzymatic reactions's rate by relating the reaction rate to the substrate's concentration. The equation is named after the two famous scientists, Leonor Michaelis and Maud Menten.

The formula is :

$v=\frac{V_{max}[S]}{K_M + [S]}$

where v = velocity of reaction

$V_{max}$ = maximum rate achieved

$K_M$ = Michaelis constant

[S] = concentration of the substrate, S

According to the question, by putting the velocity of reaction, v as $\frac{V_{max}}{4}$ , we get the above equation as

$[S]= \frac{K_M}{3}$

Therefore the answer is $[S]= \frac{K_M}{3}$

3 0

3 years ago

The following three resistors (Ohms) are in parallel with one voltage source. What is the total current running through circuit?

Zepler [3.9K]

Explanation:

The total resistance Rt is given by

1/Rt = 1/Ra + 1/Rb + 1/Rc = 1/5 + 1/4 + 1/7 = 0.593

or Rt = 1.69 ohms

The total current I running through the circuit is

I = V/Rt = 2.37 A

6 0

3 years ago

A ball is dropped from rest at point O . It passes a window with height 3.8 m in time interval tAB = 0.02 s.Identify the correct

Taya2010 [7]

Answer:

VB − VA = g tAB & (VA + VB)/2 = h / tAB

Explanation:

s = h = Displacement

tAB = t = Time taken

VA = u = Initial velocity

VB = v = Final velocity

a = g = Acceleration due to gravity = 9.8 m/s²

$s=ut+\frac{1}{2}at^2\\\Rightarrow u=\frac{s-\frac{1}{2}at^2}{t}\\\Rightarrow u=\frac{3.8-\frac{1}{2}\times 9.8\times 0.02^2}{0.02}\\\Rightarrow u=189.902\ m/s$

$v=u+at\\\Rightarrow v=189.902+9.8\times 0.02\\\Rightarrow v=190.098\ m/s$

$\frac{v+u}{2}=\frac{190.098+189.902}{2}=190\ s$

$\frac{h}{t}=\frac{3.8}{0.02}=190\ s$

Hence, the equations VB − VA = g tAB & (VA + VB)/2 = h / tAB will be used

3 0

3 years ago