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3 years ago

14

How are u guys define unification of germany

1 answer:

rjkz [21]3 years ago

5 0

The Unification of Germany into the German Empire, a Prussia-dominated nation state with federal features,[1] officially occurred on 18 January 1871 at the Versailles Palace's Hall of Mirrors in France. Princes of the German states gathered there to proclaim Wilhelm of Prussia as Emperor of the German Empire after the French capitulation in the Franco-Prussian War.

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How high was a brick dropped from if if falls in 2.5 seconds?

jenyasd209 [6]

Using the kinematic equation d = V_0 * t + 1/2 * a * t^2, where d is height you can rewrite this to be d = 1/2*g*t^2 or 4.9t^2
g = a because this is a free fall
d = 1/2 * 9.81m/s^2 * 2.5^2
d = 30.65625m
d = 30.7m

7 0

3 years ago

What is the difference about the modern times and ice ages

Rasek [7]

Answer:

The average temperature is much warmer

Explanation:

6 0

3 years ago

Three beakers are of identical shape and size , one beaker is pained matt black, one is dull white and one is gloss white . The

JulsSmile [24]

Answer:

The beaker that is matt black heats more quickly because black attracts more heat.

Explanation:

5 0

3 years ago

What kind of organism always comes last in every food chain

Elena-2011 [213]

Tertiary consumer is always at the top.
The producer is always at the bottom.

4 0

3 years ago

In the first stage of a two-stage Carnot engine, energy is absorbed as heat Q1 at temperature T1 = 500 K, work W1 is done, and e

Nataly [62]

Answer:

Efficiency = 52%

Explanation:

Given:

First stage

heat absorbed, Q₁ at temperature T₁ = 500 K

Heat released, Q₂ at temperature T₂ = 430 K

and the work done is W₁

Second stage

Heat released, Q₂ at temperature T₂ = 430 K

Heat released, Q₃ at temperature T₃ = 240 K

and the work done is W₂

Total work done, W = W₁ + W₂

Now,

The efficiency is given as:

$\eta=\frac{\textup{Total\ work\ done}}{\textup{Energy\ provided}}$

or

Work done = change in heat

thus,

W₁ = Q₁ - Q₂

W₂ = Q₂ - Q₃

Thus,

$\eta=\frac{(Q_1-Q_2)\ +\ (Q_2-Q_3)}{Q_1}}$

or

$\eta=1-\frac{(Q_1-Q_3)}{Q_1}}$

or

$\eta=1-\frac{(Q_3)}{Q_1}}$

also,

$\frac{Q_1}{T_1}=\frac{Q_2}{T_2}=\frac{Q_3}{T_3}$

or

$\frac{T_3}{T_1}=\frac{Q_3}{Q_1}$

thus,

$\eta=1-\frac{(T_3)}{T_1}}$

thus,

$\eta=1-\frac{(240\ K)}{500\ K}}$

or

$\eta=0.52$

or

Efficiency = 52%

8 0

4 years ago