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Vaselesa [24]
3 years ago
7

The following passage contains a fragment. Select the correct revision. Presley took the exuberance of gospel and added the freq

uently rapid beat of rock and roll. Which made possible the wild gyrations that established him as an international celebrity.
a. presley took the exuberance of gospel and added the frequently rapid beat of rock and​ roll, which made possible the wild gyrations that established him as an international celebrity.

b. presley took the exuberance of gospel. and added the frequently rapid beat of rock and​ roll, which made possible the wild gyrations. establishing him as an international celebrity.

c. presley took the exuberance of gospel. and added the frequently rapid beat of rock and roll. which made possible the wild gyrations that established him as an international celebrity.

d. presley took the exuberance of gospel and added the frequently rapid beat of rock and roll. which made possible the wild gyrations. that established him as an international celebrity.
Engineering
1 answer:
Semmy [17]3 years ago
7 0

Answer:

A

Explanation:

Option A was the only option that did not have a sentence fragment. All the other choices were fragments because they interrupted the flow of the sentence. A sentence fragment means that if you started reading where the period is, you would understand everything about the sentence and it would be clear. You cannot have an incomplete sentence that does not have background information. An example would be: And that is how you install it. This leaves information unanswered, such as what the subject of the sentence is, or in other words, what you were installing. Another indicator that this was a sentence fragment was that the sentence began with the word "And." Sentence fragments very commonly start with the word and, because that word shows that it is a continuation of a topic.

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I dont undertand this coding problem (Java):
chubhunter [2.5K]

Check The Attachment.

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6 0
4 years ago
Determine the slopes and deflections at points B and C for the beam shown below by the moment-area method. E=constant=70Gpa I=50
inn [45]

Answer:

hello your question is incomplete attached below is the complete question

answer :

Slopes : B = 180 mm , C = 373 mm

Deflection: B = 0.0514 rad ,  C = 0.077 rad

Explanation:

Given data :

I = 500(10^6) mm^4

E = 70 GPa

The M / EI  diagram is attached below

<u><em>Deflection angle at B</em></u>

∅B = ∅BA = [ 150 (6) + 1/2 (300)*6 ] / EI

                 = 1800 / ( 500 * 70 ) = 0.0514 rad

<u><em>slope at B </em></u>

ΔB = ΔBA = [ 150(6)*3 + 1/2 (300)*6*4 ] / EI

                 = 6300 / ( 500 * 70 ) = 0.18 m = 180 mm

<u><em>Deflection angle at C </em></u>

∅C = ∅CA = [ 1800 + 300*3 ] / EI

                 = 2700 / ( 500 * 70 )

                 = 2700 / 35000 = 0.077 rad

<u><em>Slope at C </em></u>

ΔC = [ 150 * 6 * 6 + 1/2 (800)*6*7 + 300(3) *1.5 ]

     = 13050 / 35000 = 373 mm

3 0
3 years ago
Consider liquid n-hexane in a 50-mm diameter graduated cylinder. Air blows across the top of the cylinder. The distance from the
ra1l [238]

The evaporation rate of the n-Hexane is 7.85 \times 10^{-6} \mathrm{mol} / \mathrm{s}

<u>Explanation</u>:

This is a situation regarding diffusing A through non-diffusing B.

A = n-Hexane B=Air

Where the molar flux is provided by,

N_{A}=D_{A B} P_{T}\left(P_{A 1}-P_{A 2}\right) / R T z P_{b m}

\mathrm{D}_{\mathrm{AB}}=8.8 \times 10^{-6} \mathrm{m}^{2} / \mathrm{s}

P_{t}=1 a t m=101325 P a\\

\text { so, } P_{A 1}= the vapor pressure at hexane 25 \mathrm{C} =20158.2 \mathrm{Pa}

For wind, assume negligible hexane is present, hence P_{A 2}=0

Now,

\mathrm{P}_{\mathrm{B} 1}=\mathrm{P}_{\mathrm{T}}-\mathrm{P}_{\mathrm{A} 1}=101325-20158.2 \mathrm{P}_{\mathrm{a}}

\mathrm{P}_{\mathrm{B} 2}=\mathrm{P}_{\mathrm{T}}-\mathrm{P}_{\mathrm{A} 2}=\mathrm{P}_{\mathrm{T}}=101325 \mathrm{Pa}

P_{B M}=\frac{\left(P_{B 2}-P_{B 1}\right)}{\log _{e}\left(P_{B 2} / P_{B 1}\right)}\\

=\frac{101325-81166.8}{\ln \left(\frac{101325}{81166.8}\right) \mathrm{Pa}}

=90873.57 \mathrm{Pa}

R=8.314 \mathrm{J} / \mathrm{mol}-\mathrm{K}

z=\text { distance }=20 \mathrm{cm}=0.2 \mathrm{m}\\

where T = 298 K

substituting all in the equation, we get

\begin{aligned}&\mathrm{N}_{\mathrm{A}}=\\&\left(8.8 \times 10^{-6} \mathrm{m}^{2} / \mathrm{s}\right) \times 101325 \mathrm{Pa} \times(20158.2 \mathrm{Pa}) /(8.314 \mathrm{J} / \mathrm{mol}-\mathrm{K} \times 0.2 \mathrm{m} \times 298 \mathrm{K}\\&\times 90873.57 \mathrm{Pa})\end{aligned}

=0.004 \mathrm{mol} / \mathrm{m}^{2} \mathrm{s}\\

Now,Flux \times area  = Molar rate of evaporation

Evaporation rate = 0.004 \mathrm{mol} / \mathrm{m}^{2}-5 \mathrm{x}\left(\pi \mathrm{d}^{2} / 4 \mathrm{m}^{2}\right)=0.004 \times(3.14 \times 0.05 \times 0.05 / 4)

Evaporation rate =7.85 \times 10^{-6} \mathrm{mol} / \mathrm{s}

6 0
3 years ago
When the grounded conductor is to be spliced in a 12-inch by 12-inch junction box, there shall be at least ? of free conductor l
slamgirl [31]

There should be a  6" free conductor left for splicing

Why there should be 6" splicing?

You must leave the junction box with at least six inches of free conductor wiring when running electrical cables from the box to the box for connecting needs.

Actually, 6-8 inches can be left when running the electric cables, additionally even if the grounded conductor is to be spliced in a 12-inch by 12-inch.

Conductor splicing: A splice, which can be finished using either the crimping or soldering method, is the joining of two or more conductors in a way that produces a permanent electrical termination and mechanical link.

Hence we can conclude that 6 inches is fine for the conductor splicing

To learn more about splicing
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7 0
1 year ago
Please help meeeplzzzzzz
Triss [41]

Answer:

labelled diagram for combination wrench

8 0
3 years ago
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