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ahrayia [7]
3 years ago
13

Alan and Monica tested how fertilizer X affected the growth of a plant. Alan and Monica put 100 grams of fertilizer X in pot 1.

They put 0 grams of fertilizer X in pot 2.
What is pot 2 called in science?
A.
a test group
B.
a data group
C.
an observational group
D.
a control group
Physics
1 answer:
BARSIC [14]3 years ago
7 0

Answer:

D.

a control group

Explanation:

In a scientific experiment such as the one above, there is an experimental group and a control group. The experimental group is the group that receives the treatment while the control group does not receive any treatment. The control group helps the researcher to observe if the treatment had any significant effect.

In this case, it will help Alan and Monica to determine if fertilizer X actually had an effect on the plant. Therefore, the pot with o grams of fertilizer in it is the control group.

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A fire truck emits an 880Hz siren. As the truck approaches an observer on the sidewalk, he perceives the pitch to be 950Hz. Appr
Ludmilka [50]

Answer:

The pitch that he hears after the truck passes and is moving away is 819.6 Hz.

Explanation:

The pitch that he hears after the truck passes and is moving away can be calculated using the following equation:    

f = f_{0}*\frac{v_{s} \pm v_{o}}{v_{s} \pm v_{f}}

Where:

f: is the perceived frequency

f_{0}: is the emitted frequency

v_{s}: is the speed of sound = 340 m/s

v_{o}: is the speed of the observer = 0 (he is not moving)

v_{f}: is the speed of the fire truck

First, we need to find the speed of the fire truck. When it approaches the observer we have:

f = f_{0}*\frac{v_{s} + v_{o}}{v_{s} - v_{f}}

950 Hz = 880 Hz*\frac{340 m/s}{340 m/s - v_{f}}

v_{f} = 340 m/s - \frac{880 Hz*340 m/s}{950 Hz}

v_{f} = 25.05 m/s

Hence, the speed of the fire truck is 25.05 m/s.

Now, we can calculate the pitch that the observer hears after the truck passes:

f = f_{0}*\frac{v_{s} - v_{o}}{v_{s} + v_{f}}

f = 880 Hz*\frac{340 m/s}{340 m/s + 25.05 m/s}

f = 819.6 Hz

Therefore, the pitch that he hears after the truck passes and is moving away is 819.6 Hz.

I hope it helps you!                                                          

7 0
3 years ago
How does evaporation happen on a stove<br> (dont mind the subject btw)
Shtirlitz [24]

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Answer: Evaporation happens by heat being transferred to the pot, then the pot transfering the heat to the water, which caused the water to vibrate more, eventually turning it into water vapor, which is how evaporation happens on the stove.

Explanation:

I hope this helped!

<!> Brainliest is appreciated! <!>

- Zack Slocum

*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆**☆*――*☆*――*☆*――*☆

3 0
3 years ago
Read 2 more answers
Why is there convection in the outer core and what is the result of this?
mars1129 [50]

Answer:

re believed to influence the Earth's magnetic field. ... As heat is transferred outward toward the mantle, the net trend is for the inner boundary of the liquid region to freeze, causing the solid inner core to grow

Explanation:

6 0
4 years ago
While water skiing behind her father’s boat, Letty is pulled at constant speed by a force of 164 N from the tow rope that makes
kap26 [50]

Answer:

0.265

Explanation:

Draw a free body diagram.  There are four forces:

Normal force Fn pushing up.

Weight force mg pulling down.

Tension force T at an angle θ.

Friction force Fn μ pushing left.

Sum the forces in the y direction:

∑F = ma

Fn + T sin θ − mg = 0

Fn = mg − T sin θ

Sum the forces in the x direction:

∑F = ma

T cos θ − Fn μ = 0

Fn μ = T cos θ

μ = T cos θ / Fn

μ = T cos θ / (mg − T sin θ)

Given T = 164 N, θ = 10.0°, m = 65.0 kg, and g = 9.8 m/s²:

μ = (164 N cos 10.0°) / (65.0 kg × 9.8 m/s² − 164 N sin 10.0°)

μ = 0.265

7 0
3 years ago
Two balls have masses 18 kg and 47 kg. The 18 kg ball has an initial velocity of 76 m/s (to the right) along a line joining the
BigorU [14]

Answer:

The final velocity of 18 kg ball is V_{2} = 42.09 \frac{m}{sec}

Explanation:

Mass of first ball m_{1} = 18 kg

Mass of second ball m_{2} = 47 kg

Initial velocity of 18 kg ball V_{1} = 76 \frac{m}{sec}

Initial velocity of 47 kg ball = 0

Final velocity of 18 kg ball V_{2} = ??

Final velocity of 18 kg ball  is given by the formula

V_{2} = \frac{2 m_{1} V_{1} }{m_{1} + m_{2}  }

Put all the values in above formula we get

V_{2} = 2 × 18 × \frac{76}{65}

V_{2} = 42.09 \frac{m}{sec}

Thus, the final velocity of 18 kg ball is V_{2} = 42.09 \frac{m}{sec}

3 0
3 years ago
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