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Setler79 [48]
3 years ago
9

Use VSEPR theory to decide which one of the following molecules and ions will definitely have at least one 90° bond angle in it.

(In each case except water, the central atom is the first one in the formula.)(A) AlCl4-(B) NH3(C) PCl5(D) CO2(E) H2O
Chemistry
1 answer:
seraphim [82]3 years ago
8 0

Answer:

(C) PCl₅

Explanation:

(A) AlCl₄⁻

The central atom has 4 bond pairs and 0 lone pair. Hybridization is sp³. The geometry is tetrahedral which has an angle of 109.5°.

(B) NH₃

The central atom has 3 bond pairs and 1 lone pair. Hybridization is sp³. The geometry is pyramidal which has an angle of approximately 107.5°.

(C) PCl₅

The central atom has 5 bond pairs and 0 lone pair. Hybridization is sp³d². The geometry is trigonal bipyramidal in which the equatorial bonds has an angle of 120° and axial bond has an angle of 90°.

(D) CO₂

The central atom has 4 bond pairs and 0 lone pair. Hybridization is sp. The geometry is linear which has an angle of 180°.

(E) H₂O

The central atom has 2 bond pairs and 2 lone pairs. Hybridization is sp³. The geometry is bent shape which has an angle of approximately 105.5°.

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<u>1) To show that heat flows spontaneously from high temperature to low temperature </u>

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Pick two(2) solid metal blocks with varying temperatures ( i.e. one solid block is hot and the other solid block is cold )

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