Answer: Hydrocarbons
Explanation:
Hydrocarbons refer to binary compounds of carbon and hydrogen. The carbon-hydrogen bond is no polar so hydrocarbons are non polar compounds. They are commonly used as fuels and as waxes. They may be aromatic, aliphatic or cyclic in structure.
<u>Answer:</u>
0.058 M
<u>Explanation:</u>
HBr reacts with NaOH and forms NaBr and H₂O as the products. The balanced equation is as follows:

Molarity (M) = moles of solute (mol) / volume of the solution (L)
Molarity of NaOH = 0.115 M
Volume of NaOH = 18.2 mL = 18.2 x 10⁻³ L
So, moles of NaOH = molarity x volume of the solution
= 0.115 M x 18.2 x 10⁻³ L
= 2.093 x 10⁻³ mol
From the equation, we can see that the ratio between NaOH and HBr is 1 : 1.
Therefore, moles of HBr in 35.6 mL = moles of NaOH added = 2.093 x 10⁻³ mol
Hence, molarity of HBr = 2.093 x 10⁻³ mol
/ 35.6 x 10⁻³ L = 0.058 M
They need to be confronted with a chemical that will make them react and you might need to try different chemicals.
Answer:
See Explanation
Explanation:
Given:
moles M = 0.600 mole
moles F = excess (for rxn stoichiometry)
Formula Weight (F.Wt.) of F = 19 grams/mole (from Periodic Table)
Yield in grams = 46.8 grams (assuming theoritical yield)
Rxn: M + F₂ => MF₂
0.600mol Excess 0.600mol (1:1 rxn ratio for M:MF₂)
a. moles of F in MF₂ = 2(0.600) moles F = 1.2 moles F
b. mole weight MF₂ = 46.8g/0.600mol = 78g/mole
F.Wt. MF₂ = F.Wt. M + 2(F.Wt. F)
=> mass M = F.Wt. M = [F.Wt. MF₂ - 2(F.Wt. F)] = 78g/mol. - 2(19g/mol.)
= (78 - 38) grams/mole = 40 grams/mole
c. Calcium (Ca) has F.Wt. = 40 grams/mole (compared to Calcium on Periodic Table.
Answer:
a
The condensed structural formula for methane is

b
The condensed structural formula for ethane is

c
The condensed structural formula for pentane is
d
The diagram for the structural formula for cyclopropane is shown on the first uploaded image
Explanation: