In an experiment, a research collected the following informationabout a solution made from a certain
1 answer:
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Explanation:
Given that,
Charge on a spherical drop of water is 43 pC
The potential at its surface is 540 V
(a) The electric potential on the surface is given by :
r is the radius of the drop
(b) Let R is the radius of the spherical drop, when two such drops of the same charge and radius combine to form a single spherical drop. ATQ,
Now the charge on the new drop is 2q. New potential is given by :
Hence, the radius of the drop is and the potential at the surface of the new drop is 856.79 V.