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N76 [4]
3 years ago
7

A concrete block making company is developing an aggregate capacity plan from the following sales forecast for its 6” and 8” con

crete blocks shown in the table below. Product Sales Forecasts (Concrete Blocks) 1st Quarter 2nd Quarter 3rd Quarter 4th Quarter 6” Block 2,000 1,500 1,600 1,800 8” Block 1,200 1,000 800 1,000 Ample machine capacity exists to produce the forecast. Each 6” concrete block takes an average of 20 labour-hours while each 8” concrete block takes an average of 15 labour-hours. a) Compute the aggregate number of labour-hours in each quarter. b) If the plant works the same number of days in each quarter, 13 five-day weeks on a single shift, how many workers will be required in each quarter? c) It costs $1,000 to hire a worker and $500 to lay off a worker, and inventory carrying cost is $100 for each 6” concrete block and $100 for each 8” concrete block (this means that if one 6” concrete block were held in inventory for a year, it would cost $100 for finance charge, insurance, warehousing expense, etc.). The plant works the same number of days in each quarter, 13 five-day weeks. Assuming that the quarterly demand pattern repeats from year to year, compute the cost of each of the following two aggregate plans for next year: i. Chase strategy plan. Beginning inventory in this plan is zero for both types of concrete blocks. ii. Level strategy plan. Beginning inventory in this plan is 275 for 6” concrete blocks and 200 for 8” concrete blocks.
Engineering
1 answer:
Fiesta28 [93]3 years ago
4 0

Answer:

nah ask ur mom then

Explanation:

ur mom is smarter than u then ask her dont be rude

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A person walks into a refrigerated warehouse with head uncovered. Model the head as a 25- cm diameter sphere at 35°C with a surf
galina1969 [7]

Answer:

Hello some parts of your question is missing below is the missing part

Convection coefficient = 11 w/m^2. °c

answer : 44.83 watts

Explanation:

Given data :

surface emissivity ( ε )= 0.95

head ( sphere) diameter( D )  = 0.25 m

Temperature of sphere( T )  = 35° C

Temperature of surrounding ( T∞ )  = 25°C

Temperature of surrounding surface ( Ts ) = 15°C

б  = ( 5.67 * 10^-8 )

Determine the total rate of heat loss

First we calculate the surface area of the sphere

As = \pi D^{2}  

= \pi * 0.25^2 =  0.2 m^2

next we calculate heat loss due to radiation

Qrad = ε * б * As( T^{4} - T^{4} _{s} )  ---- ( 1 )

where ;

ε = 0.95

б = ( 5.67 * 10^-8 )

As = 0.2 m^2

T = 35 + 273 = 308 k

Ts = 15 + 273 = 288 k

input values into equation 1

Qrad = 0.95 * ( 5.67 * 10^-8 ) * 0.2 ( (308)^4 - ( 288)^4 )

         = 22.83  watts

Qrad ( heat loss due to radiation ) = 22.83 watts

calculate the heat loss due to convection

Qconv = h* As ( ΔT )

           = 11*0.2 ( 35 -25 )  = 22 watts

Hence total rate of heat loss

=  22 + 22.83

= 44.83 watts

5 0
3 years ago
How much does 5 acres of land cost in the US?
Dvinal [7]

Answer:

Larson, an economist, who placed the total value of $23 trillion for the entire 1.9 billion acres of land in the United States. This means that the average cost for an acre of land is $12,000 or $60,000 for 5 acres of land. Almost half of the land in the US is used for agricultural purposes.

Explanation:

6 0
4 years ago
Which of the following is an example of an observation?
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The monkey is brown!
6 0
3 years ago
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How do you know which forces works for free bodies​
miss Akunina [59]

Answer:

Gravitational force (pulled downward by the Earth)

Normal force (pushed upward by the ground)

Applied force (pushed by the person)

Friction force (pulled opposite the direction of motion by the roughness of the ground)

5 0
3 years ago
The uniform slender rod has a mass m.
Nikolay [14]

Answer: 3/2mg

Explanation:

Express the moment equation about point B

MB = (M K)B

-mg cosθ (L/6) = m[α(L/6)](L/6) – (1/12mL^2 )α

α = 3g/2L cosθ

express the force equation along n and t axes.

Ft = m (aG)t

mg cosθ – Bt = m [(3g/2L cos) (L/6)]

Bt = ¾ mg cosθ

Fn = m (aG)n

Bn -mgsinθ = m[ω^2 (L/6)]

Bn =1/6 mω^2 L + mgsinθ

Calculate the angular velocity of the rod

ω = √(3g/L sinθ)

when θ = 90°, calculate the values of Bt and Bn

Bt =3/4 mg cos90°

= 0

Bn =1/6m (3g/L)(L) + mg sin (9o°)

= 3/2mg

Hence, the reactive force at A is,

FA = √(02 +(3/2mg)^2

= 3/2 mg

The magnitude of the reactive force exerted on it by pin B when θ = 90° is 3/2mg

6 0
3 years ago
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