Answer:
Explanation:
The electric potential energy of the electron depends on the potential difference applied between the two ends of the cable. Indeed, the electric potential energy of a charge is given by
where q is the magnitude of the charge,
Δ v is the potential difference applied
So, U depends on Δ v
Answer:
5.672/s^2 is his acceleration
Explanation:
1 minute is equal to 60 seconds. Take that and divide 340.3 by that.
Answer:
f_obs = 374.9 Hz
Explanation:
Given:
- Velocity of train A, V_a = 0 m/s
- Velocity of train B, V_b = 35.0 m/s
- Velocity of observer O, V_o = 15.0 m/s
Find:
What is the frequency from A as heard by the listener?
Solution:
- In this case determine the frequency of the source i.e Train A while we as listener move away from source at a velocity of 5 m/s. The variation of frequency through medium of air is related to the velocity of the sink or observer moving away or coming towards the source, as described by the Doppler's Effect in his equation:
f_obs = f_s * ( V_air +/- V_obs ) / ( V_air +/- V_s )
- Where,
- f_s : Frequency of the source = 392 Hz
- V_air : The velocity of sound in air = 343 m/s
- V_obs : Velocity of observer.
- V_s : Velocity of source = 0
- The frequency heard by the observer is as follows when he moves away from the source V_obs = - 15 m/s , and Velocity of source = 0. Hence using the equation:
f_obs = 392 * ( 343 - 15 ) / ( 343 + 0 )
f_obs = 374.9 Hz
Answer:
v = 10 m/s
Explanation:
recall that velocity is related to wavelength and frequency by the formula
v = fλ
where v = velocity, f = frequency and λ= wavelength
Simply substitute these into the formula:
v = fλ
v = (0.5)(20)
v = 10 m/s