A mass of 1 kg is moving in a circle of radius 3.3 meters. What is the liner velocity v m/s that would give a Centripetal Force

Question

3 years ago

13

of 23 N?

1 answer:

Ghella [55] · Answer 1 · 2022-03-09T11:10:46+03:00

Answer:

The linear velocity of the object is 8.71 m/s.

Explanation:

Given;

mass of the object, m = 1 kg

radius of the circle, r = 3.3 meters

centripetal force, F = 23 N

Centripetal force is given by;

$F_c = \frac{mv^2}{r}\\\\$

where;

v is the linear velocity of the object

$F_c = \frac{mv^2}{r}\\\\mv^2 = F_cr\\\\v^2 = \frac{F_cr}{m}\\\\v= \sqrt{\frac{F_cr}{m}} \\\\v= \sqrt{\frac{23*3.3}{1}}\\\\v = 8.71 \ m/s$

Therefore, the linear velocity of the object is 8.71 m/s.