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defon
3 years ago
10

Plz help me with is thank you

Chemistry
1 answer:
s2008m [1.1K]3 years ago
4 0

Answer:

d

Explanation:

the pattern of the chart

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"<span>(4) an increase in the activation energy of the forward reaction" is the correct answer from the list but it should be noted that this is not always the case. </span>
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a runner cruises along at 9 miles per hour. How many days will it take him to run around the world, assuming no stops? (40,076 k
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3 0
3 years ago
A solution is made by dissolving 26.42g of (NH4)2so4 in enough h2o to make 50.00ml of solution
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Moles of ammonium sulfate = 26.42/molar mass of (NH4)2SO4
                                             =   26.42/132.14 = 0.19 mole.

Molarity = moles of ammonium sulfate/volume of solution
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6 0
4 years ago
Read 2 more answers
The specific heat of liquid bromine is 0.226 J/g-K. How much heat (J) is required to raise the temperature of 10.0 mL of bromine
Viefleur [7K]

Answer:

16.2 J

Explanation:

Step 1: Given data

  • Specific heat of liquid bromine (c): 0.226 J/g.K
  • Volume of bromine (V): 10.0 mL
  • Initial temperature: 25.00 °C
  • Final temperature: 27.30 °C
  • Density of bromine (ρ): 3.12 g/mL

Step 2: Calculate the mass of bromine

The density is equal to the mass divided by the volume.

ρ = m/V

m = ρ × V

m = 3.12 g/mL × 10.0 mL

m = 31.2 g

Step 3: Calculate the change in the temperature (ΔT)

ΔT = 27.30 °C - 25.00 °C = 2.30 °C

The change in the temperature on the Celsius scale is equal to the change in the temperature on the Kelvin scale. Then, 2.30 °C = 2.30 K.

Step 4: Calculate the heat required (Q) to raise the temperature of the liquid bromine

We will use the following expression.

Q = c × m × ΔT

Q = 0.226 J/g.K × 31.2 g × 2.30 K

Q = 16.2 J

7 0
3 years ago
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<span>This theory was suggested around 450 BC</span>
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3 years ago
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