Explanation:
It is given that,
A helicopter blade spins at exactly 100 revolutions per minute.
Its tip is 5.00 m from the center of rotation, r = 5 m
(a) Let v is the average speed of the blade tip in the helicopter’s frame of reference. Distance covered by the helicopter, 
In 100 revolutions, 
So, average speed of the blade tip in one second is given by :
v = 52.35 m/s
(b) The average velocity over one revolution is zero because the net displacement in one rotation is 0.
Hence, this is the required solution.
Answer:
0.5 m/s
Explanation:
Velocity = displacement/time taken
going 15 meters east and then 20 meters west gives a displacement of 5 meters.
Velocity v = 5/10
= 0.5 m/s
Answer:
The apparent depth of (a) the fish is 5.3 cm and (b) the image of the fish is 24.8 cm.
Explanation:
According to the following equation:
where <em>nw</em> and <em>na</em> is the refractive indices of water (1.33) and air (1.00) respectively; <em>s</em> is the depth of the fish below the surface of the water; s' is the apparent depth of the fish from normal incidence and Rc is the radius of curvature of the mirror at the bottom of the tank.
Note that the bottom of the tank is assumed to be a flat mirror, therefore the radius of curvature is very large (R⇒∞).
Therefore, the above equation can be expressed as:
Now we can solve for the apparent depth of the fish.
(a) 
(Make s' subject of the formula from the above equation)
∴ 
(b) The motionless fish floats 13 cm above the mirror, therefore the image of the fish will be situated at 13 + 20 =33 cm away from the real fish.
Therefore, s = 33 cm
NB: Here, it is assumed that the water is pure, as impurities may alter the refractive index of water.
true if you are refering to the desing of the experimnt as it does identify the variable
1) -76.27
2)-119.47
3)-256.27
4)-87.07
Here’s the formula for the last one so you know how to do it. Hope this helps!!!
