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Vaselesa [24]
3 years ago
12

Cu + 2 AgNO3 Cu(NO3)2 + 2 Ag

Chemistry
1 answer:
german3 years ago
4 0

Answer:

the answer is "a" took the test

Explanation:

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Look at the image below.
lesya692 [45]
The picture please??
4 0
3 years ago
Read 2 more answers
Write the name of the compounds
blagie [28]

P2O5 = Phosphorus pentoxide

CuO = Copper (II) oxide

NH4CI = Ammonium Chloride

Mn(OH)2 = Pyrochroite

H2O2 = Hydrogen peroxide

P4S9 = Tetraphosphorus nonasulfide

CIO2 = Chlorine dioxide  

NaF = Sodium fluoride

FeSO3 = Iron (II) Sulfite

Fe(NO3)3 = Iron (III) Nitrate  

Cr(NO2)3 = Chromium (III) Nitrite

NaHCO3 = Sodium Hydrogen Carbonate  

H2PO4 = Dihydrogen Phosphate Ion  

NaCN = Sodium Cyanide  

IF7 = Iodine Heptafluoride  

PCI3 = Phosphorus Trichloride

5 0
3 years ago
Ag has an anomalous electron configuration. write the observed electron configuration of ag. express your answer in complete for
LUCKY_DIMON [66]

In Silver, the 4d orbitals will be completely filled. That implies that it does not have two electrons in the 5s orbital. The electronic configuration of Silver is :

Ag (47) = 1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^10 4p^6 5s^1 4d^10

8 0
4 years ago
What is the only thing held constant in a combined gas law problem?
vodomira [7]

Only the amount of gas is held constant.

3 0
3 years ago
A) Calculate the standard free-energy change at 25 ∘C for the following reaction:
Genrish500 [490]

Answer:

A) ΔG° = -3,80x10⁵ kJ

B) E° = 2,85V

Explanation:

A) It is possible to answer this problem using the standard ΔG's of formation. For the reaction:

Mg(s) + Fe²⁺(aq) → Mg²⁺(aq) + Fe(s)

The ΔG° of reaction is:

ΔG° = ΔGFe(s) + ΔGMg²⁺(aq) - (ΔGFe²⁺(aq) + ΔGMg(s) <em>(1)</em>

Where:

ΔGFe(s): 0kJ

ΔGMg²⁺(aq): -458,8 kJ

ΔGFe²⁺(aq): -78,9 kJ

ΔGMg(s): 0kJ

Replacing in (1):

ΔG° = 0kJ -458,8kJ - (-78,9kJ + okJ)

<em>ΔG° = -3,80x10² kJ ≡ -3,80x10⁵ kJ</em>

B) For the reaction:

X(s) + 2Y⁺(aq) → X²⁺(aq) + 2Y(s)

ΔG° = ΔH° - (T×ΔS°)

ΔG° = -629000J  - (298,15K×-263J/K)

ΔG° = -550587J

As ΔG° = - n×F×E⁰

Where n are electrons involved in the reaction (<em>2mol</em>), F is faraday constant (<em>96485 J/Vmol</em>) And E° is the standard cell potential

Replacing:

-550587J = - 2mol×96485J/Vmol×E⁰

<em>E° = 2,85V</em>

I hope it helps!

3 0
3 years ago
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