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ki77a [65]
2 years ago
12

PLEASE HELP ON MY FINAL

Chemistry
1 answer:
svet-max [94.6K]2 years ago
4 0

Answer:

The answer is D- creation of atmospheric systems that provide oxygen while absorbing carbon dioxide

Explanation:

By using elimination of choice that answer seems the most accurate.

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combustion analysis of a hydrocarbon produced 33.01g CO2 and 13.51g H2O. Calculate the empirical formula for the hydrocarbon
masya89 [10]

Answer:

\rm CH_2.

Explanation:

Carbon and hydrogen are the only two elements in a hydrocarbon. When a hydrocarbon combusts completely in excess oxygen, the products would be \rm CO_2 and \rm H_2O. The \rm C and \rm H would come from the hydrocarbon, while the \rm O atoms would come from oxygen.

Look up the relative atomic mass of these three elements on a modern periodic table:

  • \rm C: 12.011.
  • \rm H: 1.008.
  • \rm O: \rm 15.999.

Calculate the molar mass of \rm CO_2 and \rm H_2O:

M(\mathrm{CO_2}) = 12.011 + 2 \times 15.999 = 44.009\; \rm g \cdot mol^{-1}.

M(\mathrm{H_2O}) = 2 \times 1.008 + 15.999 = 18.015\; \rm g \cdot mol^{-1}

Calculate the number of moles of \rm CO_2 molecules in 33.01\; \rm g of \rm CO_2\!:

\displaystyle n(\mathrm{CO_2}) = \frac{m(\mathrm{CO_2})}{M(\mathrm{CO2})} = \frac{33.01\; \rm g}{44.009\; \rm g\cdot mol^{-1}} \approx 0.7501\; \rm mol.

Similarly, calculate the number of moles of \rm H_2O molecules in 13.51\; \rm g of \rm H_2O\!:

\displaystyle n(\mathrm{H_2O}) = \frac{m(\mathrm{H_2O})}{M(\mathrm{H_2O})} = \frac{13.51\; \rm g}{18.015\; \rm g\cdot mol^{-1}} \approx 0.7499\; \rm mol.

Note that there is one carbon atom in every \rm CO_2 molecule. Approximately0.7501\; \rm mol of \rm CO_2\! molecules would correspond to the same number of \rm C atoms. That is: n(\mathrm{C}) \approx 0.7501\; \rm mol.

On the other hand, there are two hydrogen atoms in every \rm H_2O molecule. approximately 0.7499\; \rm mol of \rm H_2O molecules would correspond to twice as many \rm H\! atoms. That is: n(\mathrm{H}) \approx 2 \times 0.7499 \; \rm mol\approx 1.500\; \rm mol.

The ratio between the two is: n(\mathrm{C}): n(\mathrm{H}) \approx 1:2.

The empirical formula of a compound gives the smallest whole-number ratio between the elements. For this hydrocarbon, the empirical formula would be \rm CH_2.

6 0
3 years ago
If you lift an object that weighs 13 pounds through a distance of 3 feet, you have done foot-pounds of work.
Katyanochek1 [597]
The answer to your statement is true 

3 0
3 years ago
Read 2 more answers
What do engineers use to test their designs of new technologies?
erica [24]
The answer Fam is B) Models
4 0
3 years ago
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An unknown metal cylinder has a mass of 34.3 g and a volume of 2.1 mL . What is the density of the metal in g / m * L ?​
saul85 [17]

Taking into account the definition of density, the density of the metal is 16.33 \frac{g}{mL}.

<h3>Definition of density</h3>

Density is a quantity that allows us to measure the amount of mass in a certain volume of a substance. Then, the expression for the calculation of density is the quotient between the mass of a body and the volume it occupies:

density=\frac{mass}{volume}

From this expression it can be deduced that density is inversely proportional to volume: the smaller the volume occupied by a given mass, the higher the density.

<h3>Density of the metal in this case</h3>

In this case, you know that:

  • Mass= 34.3 g
  • Volume= 2.1 mL

Replacing in the definition of density:

density=\frac{34.3 g}{2.1 mL}

Solving:

<u><em>density= 16.33 </em></u>\frac{g}{mL}

In summary, the density of the metal is 16.33 \frac{g}{mL}.

Learn more about density:

<u>brainly.com/question/952755?referrer=searchResults</u>

<u>brainly.com/question/1462554?referrer=searchResults</u>

6 0
2 years ago
A(n) _______________ compound is a group of atoms held together by chemical bonds.
Arlecino [84]
Is molecule an answer? It wouldn't let me see all the answers. if it is, molecule is the correct answer. they are held together by a covalent bond, I believe.
3 0
3 years ago
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