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3 years ago

Write thebalanced chemicalequationbetweenaluminiumandbromine gas

Chemistry

1 answer:

Inessa [10]3 years ago

6 0

Answer:

Al is aluminum. Bromine gas is Br2

Explanation:

Al + Br2 = AlBr3

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A sunscreen preparation contains 2.60 % by mass benzyl salicylate. If a tube contains 6.0 oz of sunscreen, how many kilograms of

Marrrta [24]

Answer : The mass of benzyl salicylate needed to manufacture 350 tubes of sunscreen are, 1.55 kg

Explanation :

As we are given that a sunscreen preparation contains 2.60 % by mass benzyl salicylate. That means, 2.60 grams of benzyl salicylate present in 100 g of solution.

First we have to convert the given mass from oz into kg.

Conversion used:

1 kg = 35.274 oz

or,

$1oz=\frac{1}{35.274}kg$

So,

$6oz=\frac{6oz}{1oz}\times \frac{1}{35.274}kg=0.1701kg$

Now we have to determine the mass of benzyl salicylate.

As, 100 g of solution contains mass of benzyl salicylate = 2.60 g

So, 0.1701 kg of solution contains mass of benzyl salicylate = $\frac{2.60g}{100g}\times 0.1701kg=0.00442kg$

Now we have to determine the mass of benzyl salicylate are needed to manufacture 350 tubes of sunscreen.

Mass of benzyl salicylate in 350 tubes of sunscreen = 0.00442 kg × 350

Mass of benzyl salicylate in 350 tubes of sunscreen = 1.55 kg

Thus, the mass of benzyl salicylate needed to manufacture 350 tubes of sunscreen are, 1.55 kg

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4 years ago

What is gonna be the density of a block charger that is 22g and 210 cm3

Taya2010 [7]

Answer:

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4 years ago

Calculate the wavelength of light emitted when each of the following transitions occur in the hydrogen atom. What type of electr

Len [333]

Answer:

a. 1875 nm

b. 4051 nm

c. 1282 nm

These all are infrared electromagnetic radiation.

Explanation:

Our strategy here is to utilize the Rydberg equation for hydrogen atom electronic transition.

1/λ = Rh x (1/n₁² - 1/n₂²) where λ is the wavelength

Rh is Rydberg constant

n₁ and n ₂ are the energy levels ( n₁ < n₂ )

Now lets star the calculations.

a. n₁ = 3, n₂ = 4

1/λ = 1.097 x 10⁷ /m x (1/3² - 1/4²) = 5.333 x 10⁵/m

λ = 1/(5.333 x 10⁵ /m) = 1.875 x 10⁻⁶ m

Converting λ to nanometers:

1.875 x 10⁻⁶ m x (1 x10⁹ nm/m) = 1875 nm

b. n₁ = 4, n₂ = 5

1/λ = 1.097 x 10⁷ /m x (1/4² - 1/5²) = 2.468 x 10⁵/m

λ = 1/(2.468 x 10⁵/m) = 4.051 x 10⁻⁶ m

4.051 x 10⁻⁶ m x (1 x10⁹ nm/m) = 4051 nm

c. n₁ = 3, n₂ = 5

1/λ = 1.097 x 10⁷ /m x (1/3² - 1/5²) = 7801 x 10⁵/m

λ = 1/(7801 x 10⁵/m) = 1282 x 10⁻⁶ m

1282 x 10⁻⁶ m x (1 x10⁹ nm/m) = 1282 nm

All of these transitions fall in the infrared region of the spectrum.

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3 years ago

Which model uses nuclear fusion Thomason model or the Bohr model (it’s the second bullet point)

Diano4ka-milaya [45]

Answer:

Aye bro you from discovery too

Explanation:

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3 years ago

How many atoms are in 3.5 grams of copper

storchak [24]

Avegadro's number = 6.02 x10^23 atoms
so
3.5g x 1mol/63.55g Cu x 6.02 x 10^23/ 1mol=3.32 x 10^22 atoms

7 0

4 years ago

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Write thebalanced chemicalequationbetweenaluminiumandbromine gas​

Write thebalanced chemicalequationbetweenaluminiumandbromine gas