I know it’s not 5 m/s I got it wrong the first time please help

12. A concave lens has a focal length of 10 cm. An object 2.5 cm high is placed 30 cm from the lens. Determine the position and

Nimfa-mama [501]

Answer:

I think 9.5

Explanation:

............

6 0

3 years ago

How can a protein outside the cell cause events to happen inside the cell?

jeka57 [31]

Answer:

Explained

Explanation:

The proteins(sometimes are called celluar ligands) outside the cell can bind to a receptor protein( generally found on the cell membranes) on the cell surface, causing it( receptor protein) to change the shape and sending a signal inside the cell.

8 0

4 years ago

A block of mass M is connected by a string and pulley to a hanging mass m.

sveticcg [70]

(b) Use Newton's second law. The net forces on block M are

• ∑ F (horizontal) = T - f = Ma … … … [1]

• ∑ F (vertical) = n - Mg = 0 … … … [2]

where T is the magnitude of the tension, f is the mag. of kinetic friction between block M and the table, a is the acceleration of block M (but since both blocks are moving together, the smaller block m also shares this acceleration), and n is the mag. of the normal force between the block and the table.

Right away, we see n = Mg, and so f = µn = 0.2Mg.

The net force on block m is

• ∑ F = mg - T = ma … … … [3]

You can eliminate T and solve for a by adding [1] to [3] :

(T - 0.2Mg) + (mg - T ) = Ma + ma

(m - 0.2M) g = (M + m) a

a = (10 kg - 0.2 (20 kg)) (9.8 m/s²) / (10 kg + 20 kg)

a = 1.96 m/s²

We can get the tension from [3] :

T = m (g - a)

T = (10 kg) (9.8 m/s² - 1.96 m/s²)

T = 78.4 N

(c/d) No time duration seems to be specified, so I'll just assume some time t before block M reaches the edge of the table (whatever that time might be), after which either block would move the same distance of

1/2 (1.96 m/s²) t

(e) Assuming block M starts from rest, its velocity at time t is

(1.96 m/s²) t

(f) After t = 1 s, block M reaches a speed of 1.96 m/s. When the string is cut, the tension force vanishes and the block slows down due to friction. By Newton's second law, we have

∑ F = -f = Ma

The effect of friction is constant, so that f = 0.2Mg as before, and

-0.2Mg = Ma

a = -0.2g

a = -1.96 m/s²

Then block M slides a distance x such that

0² - (1.96 m/s²) = 2 (-1.96 m/s²) x

x = (1.96 m/s²) / (2 (1.96 m/s²))

x = 0.5 m

(I don't quite understand what is being asked by the part that says "calculate the time taken to contact block M and pulley" …)

Meanwhile, block m would be in free fall, so after 1 s it would fall a distance

x = 1/2 (-9.8 m/s²) (1 s)

x = 4.9 m

7 0

3 years ago

Joy is taking out a car loan which she will pay back with interest. Which option will require her to pay the lowest amount in in

yawa3891 [41]

Answer:

C) Annual compounding

Explanation:

The formula for compound interest is given as

Interest = Principle × ( 1 + Interest rate )ⁿ - 1

Here,

n is the number of compounding period

and, the interest varies with the number of periods

Now,

For Annual compounding

Number of compounding period in a year will be 1

For Semi-annual compounding

Number of compounding period in a year will be 2

For Monthly compounding

Number of compounding period in a year will be 12

For Daily compounding

Number of compounding period in a year will be 365

Therefore,

For annual compounding the interest will be least.

6 0

4 years ago

Next you place the pan on a hot electric stove. While the stove is heating the pan, you use a beater to stir the water, doing 21

Masja [62]

Answer:

ΔQ = 11050.2 J

Explanation:

Assume mass of pan is 900 gm

Assuming mass of water is 100 gm

Assuming initial temperature of pan & water is Ti = 51.268 degree C

The final temperature is T_f = 77.7 degree C

The total energy required to raise temperature

$E = (m_{pan}c_{pan} + m_{water} c_{water}) \Delta T$

E = [(900)(0.9) + (100)(4.2)](26.44)

E = 32521.2 J

The energy transferred is given by

ΔQ = E-W

ΔQ = 32521.2 J - 21471 J

ΔQ = 11050.2 J

4 0

3 years ago