What is the kinetic energy of a ball when it stops moving?

What is do you understand by chemical change give example

Greeley [361]

Answer:

the type of change in which the chemical composition of an element changes is called chemical change

the best example is the formation of H2O. Since Hydrogen is an inflammable gas and oxygen is consumed by fire to keep burning, but their product - H2O is used to extinguish oxygen

6 0

3 years ago

What occurs in the A horizon of soil?

alukav5142 [94]

Im pretty sure the anservis a

7 0

3 years ago

What is the % yield when 140.0 grams of Ethylene gas (C2H4) reacts with excess chlorine to form 280.0 grams of 1,2-Dichloro Etha

KatRina [158]

Answer:

percent yield = 56.6 %

Explanation:

Data given:

mass of Ethylene gas (C₂H₄) = 140 g

actual yield of 1,2-Dichloro Ethane (C₂H₄Cl₂)= 280 g

percent yield of 1,2-Dichloro Ethane (C₂H₄Cl₂) = ?

Reaction Given:

C₂H₄ + Cl₂ -------> C₂H₄Cl₂

Solution:

First we have to find theoretical yield.

So,

Look at the reaction

C₂H₄ + Cl₂ -----—> C₂H₄Cl₂

1 mol 1 mol

As 1 mole of C give 1 mole of CH₄

Convert moles to mass

molar mass of C₂H₄ = 2(12) + 4(1)

molar mass of C₂H₄ = 24 + 4

molar mass of C₂H₄ = 28 g/mol

molar mass of C₂H₄Cl₂ = 2(12) + 4(1) + 2(35.5)

molar mass of C₂H₄Cl₂ = 24 + 4 + 71

molar mass of C₂H₄Cl₂ = 99 g/mol

Now

C₂H₄ + Cl₂ -----—> C₂H₄Cl₂

1 mol (28 g/mol) 1 mol (99 g/mol)

28 g 99 g

28 grams of Ethylene gas (C₂H₄) produce 99 grams of C₂H₄Cl₂

So

if 28 g of C₂H₄ produce 99 g of C₂H₄Cl₂ so how many grams of C₂H₄Cl₂ will be produced by 140 g of C₂H₄.

Apply Unity Formula

28 g of C₂H₄ ≅ 99 g of C₂H₄Cl₂

140 g of C₂H₄≅ X of C₂H₄Cl₂

Do cross multiply

mass of C₂H₄Cl₂ = 99 g x 140 g / 28 g

mass of C₂H₄Cl₂ = 495 g

So the Theoretical yield of 1,2-Dichloro Ethane (C₂H₄Cl₂)= 495 g

Now Find the percent yield of 1,2-Dichloro Ethane (C₂H₄Cl₂)

Formula Used

percent yield = actual yield /theoretical yield x 100 %

Put value in the above formula

percent yield = 280g / 495 g x 100 %

percent yield = 56.6 %

percent yield of 1,2-Dichloro Ethane (C₂H₄Cl₂) = 56.6 %

8 0

4 years ago

There are ________ mol of bromide ions in 0.700 L of a 0.400 M solution of AlBr

denis23 [38]

Answer:

The number of moles of AlBr3 = Molarity × Volume

= 0.400 × 0.700

= 0.28 moles

1 mole of AlBr3 gives 3 moles of Br- ions

That is

AlBr3 = Al3+ + 3Br-

Therefore, 0.045 moles of AlBr3 will yield 3 × 0.28 = 0.84 moles

Thus; they are 0.84 moles of bromide ions

5 0

2 years ago

At equilibrium, both the forward reaction and the reverse reaction occur simultaneously and at the same rate. Since the rates ar

allsm [11]

Answer : The concentration of NO is, $6.8\times 10^{-3}M$

Solution : Given,

Concentration of $N_2$ and $O_2$ = 152 M

Equilibrium constant, $K_c$ = $2.0\times 10^{-9}$

The given equilibrium reaction is,

$N_2(g)+O_2(g)\rightleftharpoons 2NO(g)$

The expression of $K_c$ will be,

$K_c=\frac{[NO]^2}{[N_2][O_2]}$

Now put all the given values in this expression, we get:

$2.0\times 10^{-9}=\frac{[NO]^2}{152\times 152}$

$[NO]=6.8\times 10^{-3}M$

Therefore, the concentration of NO is, $6.8\times 10^{-3}M$

5 0

3 years ago