The mass of 0.699 mol of C₆H₁₂O₆ is 126 g.
Mass = 0.699 mol × (180.16 g/1 mol) = 126 g
Answer:
2.3 g NaCl
Explanation:
Given the concentration of the NaCl solution = 0.92% (w/v)
It means that 0.92 g of NaCl is present in 100 mL of water.
Thus,
100 mL of water contains 0.92 g of NaCl
To find, amount of NaCl in 250 mL of water
So,
1 mL of water contains
of NaCl
250 mL of water contains
of NaCl
<u>2.3 g of NaCl is present in 250 mL of this solution.</u>
Answer:
D. 1s2,2s2,2p6,3s2,3p6,3d10,4s2,4p6,4d10,5s2,5p6
Explanation:
Hello!
In this case, since the standard iodine atom has 53 electrons, when it forms the iodide ion it is known it gains one spare electron so now it has 54; it means we need to write the new electron configuration up to 54 as shown below:
![I^-:1s^2,2s^2p^6,3s^2,3p^6,4s^2,3d^{10},4p^6,5s^2,4d^{10},5p^6.](https://tex.z-dn.net/?f=I%5E-%3A1s%5E2%2C2s%5E2p%5E6%2C3s%5E2%2C3p%5E6%2C4s%5E2%2C3d%5E%7B10%7D%2C4p%5E6%2C5s%5E2%2C4d%5E%7B10%7D%2C5p%5E6.)
Thus, the answer should be:
D. 1s2,2s2,2p6,3s2,3p6,3d10,4s2,4p6,4d10,5s2,5p6
Even when the order is not the adequate one.
Regards!