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ziro4ka [17]
3 years ago
14

16. Formaldhyde has a mole ratio of 1 mole C: 2 moles H: 1 mole O. Its empirical formula is the same as its

Chemistry
1 answer:
Dominik [7]3 years ago
6 0

Answer:

d. 97.60 g

Explanation:

Given parameters:

Number of moles of formaldehyde = 3.25moles

  Ratio:

                 C               H              O

                  1                2               1

Unknown:

Mass of this sample  = ?

Solution:

The empirical formula of a compound is its simplest formula. It is the simplest whole number ratio of the atoms in a given substance.

The molecular formula is the actual formula of the compound.

 Since the molecular and empirical formula are the same here, the formula of the compound is;

                   CH₂O

To find the mass of the formaldehyde, use the expression below;

        Mass  = number of moles x molar mass

             molar mass of CH₂O = 12 + 2(1) + 16  = 30g/mol

      Mass  = 3.25 x 30  = 97.5g

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The reaction: 2H2(g) + O2(g) → 2H2O(g), can be interpreted as: a. 2 moles of hydrogen gas reacts with 1 mole of oxygen gas to produce 2 moles of water.

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Answer:

Binary compound

Explanation:

Binary compounds:

The compounds which are made up of the atoms of only two elements are called binary compounds.

For example:

The following compounds are binary:

HCl

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HCl is binary because it is composed of only hydrogen and chlorine. Ammonia is also binary compound because it is made up of only two elements nitrogen and hydrogen.

water is also binary because it is also made up of only two elements hydrogen and oxygen.

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What energy is it when you flip on a switch on a lamp
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How many moles of Cu(OH)2 are soluble in 1L of sodium hydroxide (NaOH) when the pH is 8.23?
Morgarella [4.7K]

Answer:

4.96E-8 moles of Cu(OH)2

Explanation:

Kps es the constant referring to how much a substance can be dissolved in water. Using Kps, it is possible to know the concentration of weak electrolytes. Then, pKps is the minus logarithm of Kps.

Now, we know that sodium hydroxide (NaOH) is a strong electrolyte, who is completely dissolved in water. Therefore the pH depends only on OH concentration originating from NaOH. Let us to figure out how much is that OH concentration.

pH= -log[H]\\pH= -log (\frac{kw}{[OH]})

8.23 = - log(\frac{Kw}{[OH]} \\10^{-8.23} = Kw/[OH]\\ [OH] = Kw/10^{-8.23}

[OH]=1.69E-6

This concentration of OH affects the disociation of Cu(OH)2. Let us see the dissociation reaction:

Cu(OH)_2 -> Cu^{2+} + 2OH^-

In the equilibrum, exist a concentration of OH already, that we knew, and it will be added that from dissociation, called "s":

The expression for Kps is:

Kps= [Cu^{2+}] [OH]^2

The moles of (CuOH)2 soluble are limitated for the concentration of OH present, according to the next equation.

Kps= s*(2s+1.69E-6)^2

"s" is the soluble quantity of Cu(OH)2.

The solution for this third grade equation is s=4.96E-8 mol/L

Now, let us calculate the moles in 1 L:

moles Cu(OH)_2 = 4.96E-8 mol/L * 1 L = 4.96E-8 moles

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How many molecules of calcium chloride are in 3CaCl2
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