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maks197457 [2]
3 years ago
13

James is preparing three solutions of salt water. Each of the solutions has the same amount of water in the beaker and a differe

nt amounts of salt. In the first beaker, there is one scoop of salt in the beaker. The second beaker has two scoops of salt. The third beaker has three scoops of salt. Which of the beakers is the most concentrated solution?
Chemistry
2 answers:
jeyben [28]3 years ago
8 0
The third beaker: since it has the most amount of salt and  the same amount of water as all the other beakers . So it has the highest concentrated amount :)

Lemur [1.5K]3 years ago
3 0

Answer: the beaker 3

Explanation: that what it said on usatestprep

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The photodissociation of ozone by ultraviolet light in the upper atmosphere is a first-order reaction with a rate constant of 1.
atroni [7]

Answer:

[O₃]= 8.84x10⁻⁷M  

Explanation:

<u>The photodissociation of ozone by UV light is given by:</u>

O₃ + hν → O₂ + O (1)

<u>The first-order reaction of the equation (1) is:</u>

rate = k [O_{3}] = - k \frac{\Delta [O_{3}]}{\Delta t} (2)

<em>where k: is the rate constant and Δ[O₃]/Δt: is the variation in the ozone concentration with time, and the negative sign is by the decrease in the reactant concentration </em>    

<u>We can get the following expression of the </u><u>first-order integrated law</u><u> of the reaction (1), by resolving the equation (2):</u>

[O_{3}]_{t} = [O_{3}]_{0} \cdot e^{-kt} (3)

<em>where [O₃](t): is the ozone concentration in the elapsed time and [O₃]₀: is the initial ozone concentration</em>

We can calculate the initial ozone concentration using equation (3):  

[O_{3}]_{t} = 5.0 \cdot 10^{-3}M \cdot e^{-(1.0\cdot 10^{-5}s^{-1}) (\frac{10d \cdot 24h \cdot 3600 s}{1d \cdot 1h})} = 8.84 \cdot 10^{-7}M

So, the ozone concentration after 10 days is 8.84x10⁻⁷M.

I hope it helps you!                    

3 0
3 years ago
What other elements does iron commonly bonds with.
Neko [114]

☁️ Answer ☁️

annyeonghaseyo!

Your answer is:

it can bond with oxygen to form rust or iron oxide. and it can bond with carbon to form steel.

Here's another one: Iron bonds with lots of things: Oxygen (Ferric Oxide = rust),Chlorine (Ferric Chloride]), Fluorine, ... , even other Iron (in aMetallic Bond or crystal).

Hope it helps.

Have a nice day hyung/noona!~  ̄▽ ̄❤️

5 0
2 years ago
What is microorganisms
Wewaii [24]

Answer:

Technically a microorganism or microbe is an organism that is microscopic. The study of microorganisms is called microbiology. Microorganisms can be bacteria, fungi, archaea or protists. The term microorganisms does not include viruses and prions, which are generally classified as non-living.

4 0
2 years ago
A titration was performed in a lab situation. H2SO4 was titrated with NaOH. The following data was collected: mL of NaOH used =
RoseWind [281]
For the titration we use the equation,
                             M₁V₁ = M₂V₂
where M is molarity and V is volume. Substituting the known values,
                            (0.15 M)(43.2 mL) = (2)(M₂)(20.5 mL)
We multiply the right term by 2 because of the number of H+ in H2SO4. Calculating for M₂ will give us 0.158 M. Thus, the answer is approximately 0.16M. 
7 0
3 years ago
Read 2 more answers
What volume of solution must be added to 4.0 mol of NaCl to make a 1.2 M solution?
Aleksandr [31]

Answer:

\boxed {\boxed {\sf 3.3 \ liters}}}

Explanation:

Molarity is a measure of concentration in moles per liter.

molarity=\frac{moles \ of \ solute}{liters \ of \ solution}}

The solution has a molarity of 1.2 M or 1.2 moles per liter. There are 4.0 moles of NaCl, the solute. We don't know the liters of solution, so we can use x.

  • molarity= 1.2 mol/L
  • moles of solute= 4.0 mol
  • liters of solution =x

Substitute the values into the formula.

1.2 \ mol/L = \frac{4.0 \ mol}{x}

Since we are solving for x, we must isolate the variable. Begin by cross multiply (multiply the 1st numerator and 2nd denominator, then the 1st denominator and 2nd numerator.

\frac {1.2 \ mol/L}{1}=\frac{ 4.0 \ mol}{x}

4.0 \ mol *1=1.2 \ mol/L *x

4.0 \ mol = 1.2 \ mol/L *x

x is being multiplied by 1.2 moles per liter. The inverse of multiplication is division, so divide both sides by 1.2 mol/L

\frac{4.0 \ mol}{1.2 \ mol/L} = \frac{1.2 \ mol/L *x}{1.2 \ mol/L}

\frac{4.0 \ mol}{1.2 \ mol/L}=x

The units of moles (mol) will cancel.

\frac{4.0 }{1.2 } \ L =x

3.33333333 \ L=x

The original measurements both have 2 significant figures, so our answer must have the same. For the number we found, this is the tenths place.

The 3 in the hundredth place tells us to leave the 3 in the tenths place.

3.3 \ L\approx x

Approximately  <u>3.3 liters of solution</u> are needed to make a 1.2 M solution with 4.0 moles of sodium chloride.

7 0
3 years ago
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