Answer:
Photosynthesis gas, is called carbon dioxide. Carbon Dioxide in this process is where the plants take in the dioxide and water, which is slowly reduced which gains electrons! :)
Explanation:
Hope this helps ! plz mark as brainliest!
Answer:
Protons, electrons, same in that order is the answer.
Explanation:
this has to do with the periodic table information.
<span>The rate of infusion is 2.1L/19h or 2100mL/19h (as 1L = 100 mL).
To convert 19 hours to minutes we multiply as follows:
19 hours = (19 hours) x (60 minutes/1 hour) = 1140 minutes
So the rate of infusion becomes:
2100mL /1140 min
In order to converted mL to drops (gtt) we multiply the rate of infusion with the drop factor to get the drip rate:
(2100mL/1140min) x (20 gtt/mL) = 36.8 gtt/min</span>
The question is incomplete, the complete question is;
1.000 atm of Oxygen gas, placed in a container having apinhole opening in its side. leaks from the container 2.14 timesfaster thatn 1.000 atm of an unknown gas placed in this sameapparatus. Which of the following species could be theunknown gas?
A. CL2
B. SF6
C. Kr
D. UF6
E. Xe
Answer:
SF6
Explanation:
From Graham's law;
Let the rate of diffusion of oxygen be R1
Let the rate of diffusion of unknown base be R2
Let the molar mass of oxygen by M1
Let the molar mass of unknown gas be M2
Hence;
R1/R2 = √M2/M1
So;
2.14/1 = √M2/32
(2.14/1)^2 = M/32
M= (2.14/1)^2 × 32
M= 146.6
This is the molar mass of SF6 hence the answer above.
<h3>
Answer:</h3>
3.11 moles
<h3>
Explanation:</h3>
We are given 56 g of water (H₂O)
Required to calculate the number of moles of water.
- The relationship between moles, mass and molar mass is given by;
- Moles = Mass ÷ molar mass
in this case;
- Mass of water = 56 g
- Molar mass of water = 18.02 g/mol
Therefore;
Moles of water = 56 g ÷ 18.02 g/mol
= 3.11 moles
Therefore, moles of water in 56 g will be 3.11 moles
