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maks197457 [2]
3 years ago
13

James is preparing three solutions of salt water. Each of the solutions has the same amount of water in the beaker and a differe

nt amounts of salt. In the first beaker, there is one scoop of salt in the beaker. The second beaker has two scoops of salt. The third beaker has three scoops of salt. Which of the beakers is the most concentrated solution?
Chemistry
2 answers:
jeyben [28]3 years ago
8 0
The third beaker: since it has the most amount of salt and  the same amount of water as all the other beakers . So it has the highest concentrated amount :)

Lemur [1.5K]3 years ago
3 0

Answer: the beaker 3

Explanation: that what it said on usatestprep

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When nitrogen dioxide gas dissolves in water, an aqueous solution containing dissolved nitric acid and nitrogen monoxide forms.
xeze [42]

Answer:

1. Based on the given question, 138.03 grams of NO₂ is reacting completely with 18.02 grams of H2O. However, in case when 359 grams of NO₂ is used then the grams of water consumed in the reaction will be,  

= 359 × 18.02 / 138.03 = 46.87 grams of water.  

2. As mentioned in the given case 138.03 grams of NO₂ generates 126.04 grams of HNO₃. Therefore, 359 grams of NO₂ will produce,  

= 359 × 126.04 / 138.03  

= 327.81 grams of HNO₃.  

3. Based on the given question, 138.04 grams of NO₂ is generating 30.01 grams of NO. Therefore, 359 grams of NO₂ will generate,  

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In which of the following sets is the symbol of the element, the number of protons, and the number of electrons given correctly?
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In, 49 protons, 49 electrons

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How many levels of full body protective clothing are there
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Which of the following properties can be
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One cup of fresh orange juice contains 115 mg of ascorbic acid (vitamin c, c6h8o6). given that one cup
kodGreya [7K]
The question is incomplete. Complete question is read as:
'<span>One cup of fresh orange juice contains 115 mg of ascorbic acid (vitamin C, C6H8O6). Given that one cup = 218.0 mL calculate the molarity of vitamin C in organic juice.'
..........................................................................................................................
Answer:
Given: weight of solute (ascorbic acid) = 115 mg = 0.115 g
Volume of solution = 218.0 mL = 0.218 L
Molecular weight of ascorbic acid = 176.12 g/mol.

Now, Molarity = </span>\frac{\text{weight of solute(g)}}{\text{Molecular weight X Vol. of solution(l)}}
                       = \frac{\text{0.115}}{\text{176.12 X 0.218}}
<span>                       = 0.002995 mol/dm3

Answer: Molarity of solution = </span>0.002995 mol/dm3<span>

</span>
4 0
3 years ago
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