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maks197457 [2]
3 years ago
13

James is preparing three solutions of salt water. Each of the solutions has the same amount of water in the beaker and a differe

nt amounts of salt. In the first beaker, there is one scoop of salt in the beaker. The second beaker has two scoops of salt. The third beaker has three scoops of salt. Which of the beakers is the most concentrated solution?
Chemistry
2 answers:
jeyben [28]3 years ago
8 0
The third beaker: since it has the most amount of salt and  the same amount of water as all the other beakers . So it has the highest concentrated amount :)

Lemur [1.5K]3 years ago
3 0

Answer: the beaker 3

Explanation: that what it said on usatestprep

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Answer:

Kc = 1.54e - 31 / 2.61e - 24

Explanation:

1 )   N_{2}(gas) + O_{2}(gas)\rightarrow 2NO(gas)  ; Kc = 1.54e - 31

2)   N_{2}(gas) + 1/2O_{2}(gas)\rightarrow N_{2}O(gas)  ; Kc = 2.16e - 24

   upon reversing  ( 2 )  equation

     N_{2}O(gas)\rightarrow N_{2}(gas) + 1/2O_{2}(gas)   Kc = 1/2.16e - 24  

    now adding 1 and reversed equation (2)

       N_{2}(gas) + O_{2}(gas)\rightarrow 2NO(gas)

      N_{2}O(gas)\rightarrow N_{2}(gas) + 1/2O_{2}(gas)

   we get ,

                  N_{2}O(gas) + 1/2O_{2}(gas)\rightarrow 2NO(gas)  Kc = 1.54e-31 × 1/2.61e - 24

       equilibrium constant of equation (3) is -

            Kc = 1.54e - 31 / 2.61e - 24

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