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A 50g ball is released from rest 1.0 above the bottom of thetrack

ludmilkaskok [199]

Answer:

The maximum height of the ball is 2 m.

Explanation:

Given that,

Mass of ball = 50 g

Height = 1.0 m

Angle = 30°

The equation is

$y=\dfrac{1}{4}x^2$

We need to calculate the velocity

Using conservation of energy

$\Delta U_{i}+\Delta K_{i}=\Delta K_{f}+\Delta U_{f}$

Here, ball at rest so initial kinetic energy is zero and at the bottom the potential energy is zero

$\Delta U_{i}=\Delta K_{f}$

Put the value into the formula

$mgh=\dfrac{1}{2}mv^2$

Put the value into the formula

$50\times10^{-3}\times9.8\times1.0=\dfrac{1}{2}\times50\times10^{-3}\times v^2$

$v^2=\dfrac{2\times50\times10^{-3}\times9.8\times1.0}{50\times10^{-3}}$

$v=\sqrt{19.6}$

$v=4.42\ m/s$

We need to calculate the maximum height of the ball

Using again conservation of energy

$\dfrac{1}{2}mv^2=mgh$

Here, h = y highest point

Put the value into the formula

$\dfrac{1}{2}\times50\times10^{-3}\times(4.42)^2=50\times10^{-3}\times9.8\times h$

$y=\dfrac{0.5\times(4.42)^2}{9.8}$

$y=0.996\ m$

Put the value of y in the given equation

$y=\dfrac{1}{4}x^2$

$x^2=4\times0.996$

$x=\sqrt{4\times0.996}$

$x=1.99\ m\ \approx 2 m$

Hence, The maximum height of the ball is 2 m.

4 0

3 years ago

The escape speed from an object is v2 = 2GM/R, where M is the mass of the object, R is the object's starting radius, and G is th

Rom4ik [11]

Answer:

Approximate escape speed = 45.3 km/s

Explanation:

Escape speed

$v=\sqrt{\frac{2GM}{R}}$

Here we have

Gravitational constant = G = 6.67 × 10⁻¹¹ m³ kg⁻¹ s⁻²

R = 1 AU = 1.496 × 10¹¹ m

M = 2.3 × 10³⁰ kg

Substituting

$v=\sqrt{\frac{2\times 6.67\times 10^{-11}\times 2.3\times 10^{30}}{1.496\times 10^{11}}}=4.53\times 10^4m/s=45.3km/s$

Approximate escape speed = 45.3 km/s

6 0

3 years ago

SOMEONE HELP ASAP PLSS

kirill115 [55]

–0.05 m/s

Explanation:

The total momentum of the system player+basketball must be conserved before and after the ball has been thrown.

Before throwing the ball, the total momentum of the system is zero, because can assume both the player and the basketball being at rest:

$p_i$

The total momentum after the ball has been thrown is instead the sum of the momenta of the the player and of the basketball:

$p_f=m_p v_p + m_b v_b$

where

$m_p = 59 kg$ is the player's mass

$v_p$ is the player's velocity

$m_b=0.51 kg$ is the ball's mass

$v_b=6 m/s$ is the ball's velocity

For the conservation of momentum, we have

$p_i=p_f$

$0=m_p v_p + m_b v_b$

$v_p=-\frac{m_b v_b}{m_p}=-\frac{(0.51 kg)(6 m/s)}{59 kg}=-0.05 m/s$

And the negative sign means that the player travels in the opposite direction to the ball.

8 0

3 years ago

Read 2 more answers

compare the magnitude and range of the four basic forces—gravitational, electromagnetic, weak nuclear and strong nuclear

Andrews [41]

Answer:

The four fundamental forces magnitude and range are in order of Strong Nuclear Force > electromagnetic force > weak nuclear force > gravitational force.

Explanation:

The 4 fundamental force are weak nuclear force, strong nuclear force, em force and the gravitational force are discussed below.

Strongest force is the strong nuclear force as compared to all of them. It is very useful for capturing the atoms nucleus together despite the large repulsion which is occur between the same charges due to protons in the nucleus.

Electromagnetic Force is the 2nd strongest fundamental force. Magnetism and electricity was thought to be of 2 separate forces.

Weak Nuclear Force involves the W and Z bosons exchange. It has a very short range of

Gravitational Force is the weakest between all the fundamental forces. However, due to its long range it is the most dominant force. It follows the inverse square law like but it is always attractive in nature.

6 0

3 years ago

Please help!!!!!!! (attached to the file)

frozen [14]

Answer:

B

Explanation:

the battery isn't chemical energy so any answer saying that you can cross out and that leaves you with B

6 0

3 years ago