Question

Calculate the total binding energy, and the binding energy per nucleon, for 73Li. The masses of the atoms of 73Li and 11H are 7.016004 u and 1.007825 u, respectively. The mass of a neutron is 1.008665 u.

Answer 1

Answer:

5.60 Mev

Explanation:

Binding Energy is termed as the total energy required for the breakdown of a nucleus to its component nucleons

From the given question;

There are 3H and 4n,

Therefore;

since the masses of the atoms are 7.016004 u and 1.007825 u,

Then

3(1.007825) + 4(1.008665) = 7.058135 u

( 7.058135 - 7.016004) × (931.5) = 39.24 MeV total biding energy.

The energy per nucleon is  therefore calculate as:

$\frac {39.24 \ \ MeV }{7}$

=5.60 Mev

Thus, the total binding energy is = 5.60 Mev