Answer:
Explanation:
Mole = no. Molecules/6.02×10^23
Mole = (2.4×10^25)/(6.02×10^23)
Mole = 39.87mole
Molar mass of NaHCO3 is
= 23 + 1 + 12 + 3(16)
= 84g/mol
Mole = mass/molar mass
Mass = Mole × molar mass
Mass = 39.87 × 84
Mass= 3348.84g
The hydrogen bonds is an intermolecular force.
This is, it is an atracction among molecules, which trends to keep the molecules close one to each other quite strongly.
Vaporization is the pass from liquid, where the molecules are pretty close one to each other, to gas, where the molecules are more distant from each other. To reach that separation of the molecules, the strong hydrogen bonds must be overcome, which means a higher energy requirement than in similar compounds without hydrogen bonds.
That is reflected in high values for the enthalpy of vaporization in the compounds with hydrogen bonds (like hydrogen halides).
So, that leads to the option D. of the list of answers. enthalpy heat of vaporization gives the best indication of the relative strenght of hydrogen bonds.
Number of grams in 1 mole = 6.23 * 10^23
Now, in 15, it would be: 15 / 6.23 * 10^23 = 2.5 * 10^-24 moles (approx.)
In short, Your Answer would be Option C
Hope this helps!
A polar aprotic solvent is a polar solvent that does not have a hydrogen atom.
A polar protic solvent is a solvent that contains hydrogen. Water, ethanol and acetic acid are all examples of a polar protic solvent. A polar aprotic solvent is a polar solvent that does not contain hydrogen. Dimethyl sulphoxide, acetonitrile and dichloromethane are all examples of polar aprotic solvents.
The following are true about polar aprotic solvent.
- Acetone is a polar aprotic solvent because it cannot act as a hydrogen-bond donor.
- A polar aprotic solvent solvates cations by ion-dipole interactions.
Polar aprotic solvents solvates cations because the negative end of the dipole can interact well with the cation. Polar aprotic solvents interacts with ions by ion - dipole interaction.
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