False I think
Hope this helped ^^;
The y-component of the velocity of the carrion is equal to zero. That being said, the time it takes for the carrion to reach the ground (as close as possible to the fox) can be calculated through the equation,
d = Vot + 0.5gt²
where d is the distance, Vo is initial velocity (in this case, zero), g is the acceleration due to gravity (9.8 m/s²). Substituting the known values,
14 = 0.5(9.8)(t²)
t = 1.69 seconds
Since the horizontal component of the velocity is 1.5 m/s, the distance from the base of the tree to the point where the carrion will fall is equal to,
(1.5 m/s)(1.69 s) = 2.535 m
We add this to the given distance of the fox from the base of the tree to determine the distance of the fox from the carrion.
total distance = 2.535 m + 7 m = 9.535 m
Given that the time it takes for it to travel would only be 1.69 seconds, the speed would then be,
speed = (9.535 m) / (1.69 s) = 5.64 m/s
<em>ANSWER: speed = 5.64 m/s</em>
A- sulfur oxide
B- carbon monoxide
Answer:
Speed =
Explanation:
Speed = wavelength × frequency
Speed = 370 × 2.30 = 851m/s
Answer:
0.785 m/s
Explanation:
Hi!
To solve this problem we will use the equation of motion of the harmonic oscillator, <em>i.e.</em>
- (1)
- (1)
The problem say us that the spring is released from rest when the spring is stretched by 0.100 m, this condition is given as:
Since cos(0)=1 and sin(0) = 0:
We get
Now it say that after 0.4s the weigth reaches zero speed. This will happen when the sping shrinks by 0.100. This condition is written as:
Since
This is the same as:
We know that cosine equals to -1 when its argument is equal to:
(2n+1)π
With n an integer
The first time should happen when n=0
Therefore:
π = 0.4ω
or
ω = π/0.4 -- (2)
Now, the maximum speed will be reached when the potential energy is zero, <em>i.e. </em>when the sping is not stretched, that is when x = 0
With this info we will know at what time it happens:
The first time that the cosine is equal to zero is when its argument is equal to π/2
<em>i.e.</em>
And the velocity at that time is:
But sin(π/2) = 1.
Therefore, using eq(2):
And so: