1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Soloha48 [4]
2 years ago
7

A −4.00 μC charge sits in static equilibrium in the center of a conducting spherical shell that has an inner radius 3.13 cm and

an outer radius 4.13 cm. The shell has a net charge of −6.43 μC. Determine the charge on each surface of the shell and the electric field just outside the shell.
charge on inner surface of shell μC
charge on outer surface of shell μC
magnitude of electric field just outside the shell N/C
Physics
1 answer:
Mariulka [41]2 years ago
5 0

Answer:

(a). The charge on the outer surface is −2.43 μC.

(b). The charge on the inner surface is 4.00 μC.

(c). The electric field outside the shell is 3.39\times10^{7}\ N/C

Explanation:

Given that,

Charge q₁ = -4.00 μC

Inner radius = 3.13 m

Outer radius = 4.13 cm

Net charge q₂ = -6.43 μC

We need to calculate the charge on the outer surface

Using formula of charge

q_{out}=q_{2}-q_{1}

q_{out}=-6.43-(-4.00)

q_{out}=-2.43\ \mu C

The charge on the inner surface is q.

q+(-2.43)=-6.43

q=-6.43+2.43= 4.00\ \mu C

We need to calculate the electric field outside the shell

Using formula of electric field

E=\dfrac{kq}{r^2}

Put the value into the formula

E=\dfrac{9\times10^{9}\times6.43\times10^{-6}}{(4.13\times10^{-2})^2}

E=33927618.73\ N/C

E=3.39\times10^{7}\ N/C

Hence, (a). The charge on the outer surface is −2.43 μC.

(b). The charge on the inner surface is 4.00 μC.

(c). The electric field outside the shell is 3.39\times10^{7}\ N/C

You might be interested in
How would the terminal velocity of a piece of tissue paper compare to the terminal velocity of a rock?
matrenka [14]

Answer: Rock require larger drag force and to achieve it rock need to move at a very high terminal velocity.  

Explanation: Terminal velocity is defined as the final velocity attained by an object falling under the gravity. At this moment weight is balanced by the air resistance or drag force and body falls with zero acceleration i.e. with a constant velocity.

Case 1: Terminal velocity of a piece of tissue paper.

The weight of tissue paper is very less and it experiences an air resistance while falling downward under the effect of gravity.

Downward gravitational force, F = mg

Upward air resistance or friction or drag force will be f_{1}

So, paper will attain terminal velocity when mg =  f_{1}

Case 2: Rock is very heavy and require larger air resistance to balance the weight of rock relative to the tissue paper case.

Downward force on rock, F = Mg

Drag force = f_{2}

Rock will attain terminal velocity when Mg = f_{2}

Mg > mg

so, f_{2} > f_{1}

And rock require larger drag force and to achieve it rock need to move at a very high terminal velocity.  

5 0
3 years ago
Choose the false statement regarding resistance.
Afina-wow [57]

Answer:

i think D I hope this helps!!!!

4 0
3 years ago
Read 2 more answers
The blood pressure in the human body is greater at the feet than at the brain
GarryVolchara [31]
Blood pressure is greater in feet because of gravity
5 0
3 years ago
Read 2 more answers
Estimate the boiling point of water at a pressure of 1.1 atmosphere
Nezavi [6.7K]
It is about 100oC at a pressure of 1.1 atmosphere. Hope this helps.
4 0
3 years ago
A student gives a 5.0 kg box a brief push causing the box to move with an initial speed of 8.0 m/s along a rough surface. The bo
WITCHER [35]

Answer:

The time taken to stop the box equals 1.33 seconds.

Explanation:

Since frictional force always acts opposite to the motion of the box we can find the acceleration that the force produces using newton's second law of motion as shown below:

F=mass\times acceleration\\\\\therefore acceleration=\frac{Force}{mass}

Given mass of box = 5.0 kg

Frictional force = 30 N

thus

acceleration=\frac{30}{5}=6m/s^{2}

Now to find the time that the box requires to stop can be calculated by first equation of kinematics

The box will stop when it's final velocity becomes zero

v=u+at\\\\0=8-6\times t\\\\\therefore t=\frac{8}{6}=4/3seconds

Here acceleration is taken as negative since it opposes the motion of the box since frictional force always opposes motion.

5 0
3 years ago
Other questions:
  • Bees can see into the ultraviolet region of the electromagnetic spectrum. Compared with humans, bees can sense
    6·2 answers
  • A point charge q = -0.45 nC is fixed at the origin. Where must an electron be placed in order for the electric force acting on i
    9·1 answer
  • According to Bohr each orbit an electron could travel in had a certain amount of ________ associated with it.
    5·1 answer
  • An on-farm diesel fuel tank is on a stand 5 feet above the ground. The tank is vented to the atmosphere (the air in the tank is
    5·1 answer
  • What is WgWgW_g, the work done on the block by the force of gravity as the block moves a distance LLL up the incline? Express th
    9·1 answer
  • In hydroelectric dams, gravitational potential energy is used to produce electrical energy. What is the mass of water that must
    10·1 answer
  • When developing an experimental design, which action could a scientist take to improve the quality of the results?
    14·1 answer
  • Despite the attempts of the US, Egypt and __ , in 1978 to achieve peace in the Middle East, which region continues to be plagued
    6·1 answer
  • Why is the cathode ray oscilloscope evacuated?
    13·1 answer
  • I've been on this for a while please help me
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!