1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Romashka [77]
3 years ago
13

the mass of a large car is 1000 kg. how much force would be required to accelerate the car at a rate of 3 m/sec²​

Physics
1 answer:
jek_recluse [69]3 years ago
5 0

Answer:

3000  N

Explanation:

<em>Newton's second law of motion</em> describes the relationship between an object's mass and the amount of force needed to accelerate it.  

This law can be expresses as F=ma,

where  

  • F -  force acting on an object
  • m-  the mass of an object  
  • a -  its acceleration

The more mass an object has, the more force you need to accelerate it. And the greater the force, the greater the object's acceleration.

<em>F = ma</em>

<em>F = 1000×3 </em>

<em>   = 3000  N</em>

You might be interested in
A force of 4 kg weight acts on a body of mass 9.8 kg calculate the acceleration
White raven [17]

Answer:

here given is a weight

then force becomes mg

that is F=Mg

=4*9.8

then by using the formula

F=Ma

a=F/M

=4*9.8/9.8

=4

Explanation:

3 0
3 years ago
Read 2 more answers
Consider a sample of gas in a container on a comfortable spring day in chicago, il. the celsius temperature suddenly doubles, an
Vinil7 [7]

To solve this problem, we must first assume that the gas acts like an ideal gas so that we can use the ideal gas equation:

 P V = n R T

where P is the pressure, V is the volume, n is the number of moles, R is the universal gas constant and T is the absolute temperature

 

Assuming that the number of moles is constant, then we can write all the variables in the left side:

P V / T = k            where k is a constant (n times R)

 

Equating two conditions or two states:

P1 V1 / T1 = P2 V2 / T2

We are given that V2 = 2 V1 therefore

P1 V1 T2 = P2 (2V1) T1

P1 T2 = 2 P2 T1

 

Additionally we are given that the temperature in Celsius is doubled, however in the formula we use the absolute temperature in Kelvin, therefore:

T1 (K) = T1 + 273.15

T2 (K) = 2T1 + 273.15

and P1 = 12 atm

 

Substituting:

<span>12 (2T1 + 273.15)  = 2 P2 (T1 + 273.15)</span>

P2 = 6 (2T1 + 273.15) / (T1 + 273.15)

 

Assuming that a nice spring day in Chicago has a temperature of 15 Celsius, therefore:

P2 = 6 (2*15 + 273.15) / (15 + 273.15)

<span>P2 = 6.312 atm</span>

3 0
3 years ago
To do work, this truck uses energy stored in chemical
GREYUIT [131]

800 J Got it right on edgenuity

4 0
3 years ago
The charges Q1=Q and Q2=4Q that are a distance d apart, repel each other with a force of 1.60 N. What would be the force between
gladu [14]

Answer:

50.4 N

Explanation:

Q1 = Q

Q2 = 4 Q

Distance = d

The force is given by

F = \frac{KQ_{1}Q_{2}}{d^{2}}

1.60 = \frac{4KQ^{2}}{d^{2}}    .... (1)

Now,

Q3 = 2 Q

Q4 = 7 Q

distance = d/3

F' = \frac{9KQ_{3}Q_{4}}{d^{2}}

F' = \frac{126KQ^{2}}{d^{2}}   .... (2)

Divide equation (2) by equation (1), we get

F' / 1.60 = 126 / 4

F' = 50.4 N

Thus, the force is 50.4 N.

7 0
3 years ago
A force of 10 N acts on an object with a mass of 10 kg. What is its acceleration? A. 1 m/s2 B. 10 m/s2 C. 2 m/s2 D. 5 m/s2
Akimi4 [234]

The acceleration exerted by the object of mass 10 kg is \mathbf{1} m / \boldsymbol{s}^{2}

Answer: Option A

<u>Explanation:</u>

According to Newton’s second law of motion, any external force acting on a body will be directly proportional to the mass of the body as well as acceleration exerted by the body. So, the net external force acting on any object will be equal to the product of mass of the object with acceleration exerted by the object. Thus,

                  Force = Mass \times Acceleration

So,

                 Acceleration=\frac{\text {Force}}{\text {Mass}}

As the force acting on the object is stated as 10 N and the mass of the object is given as 10 kg, then the acceleration will be

                  Acceleration =\frac{10 \mathrm{N}}{10 \mathrm{kg}}=1 \mathrm{m} / \mathrm{s}^{2}

So, the acceleration exerted by the object of mass 10 kg is \mathbf{1} m / \boldsymbol{s}^{2}

4 0
3 years ago
Other questions:
  • A merry-go-round rotates at the rate of 0.14 rev/s with an 84 kg man standing at a point 2.4 m from the axis of rotation. What i
    9·1 answer
  • A cross-country skier moves 32 meters westward, then 54
    7·1 answer
  • Two football players with mass 75 kg and 100 kg run directly toward each other with speeds of 6 m/s and 8 m/s respectively. if t
    15·1 answer
  • A collar A of mass m is moving with a speed v when it strikes an identical collar B that is at rest. Knowing that the coefficien
    6·1 answer
  • When a plane flies with the​ wind, it can travel 1575 miles in 3.5 hours. when the plane flies in the opposite​ direction, again
    11·1 answer
  • What is the experimental group(s)?
    8·1 answer
  • A response to a touch on the palm of the hand observable in newborns is known as __________.
    7·1 answer
  • Two spectators at a soccer game in Montjuic Stadium see, and a moment later hear, the ball being kicked on the playing field. Th
    11·1 answer
  • What is the unit for measuring electric current?<br> A.Volt<br> B.ampere<br> C.ohm<br> D.coulomb
    5·2 answers
  • A student lists a set of materials
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!