All categories

2 years ago

A catalyst accelerates a reaction because:_____.

Chemistry

1 answer:

Margaret [11]2 years ago

3 0

Answer:

D. Lowering activation energy for the reaction

Explanation:

Catalysts increase the rate of a reaction without being used up. They do this by lowering the activation energy needed. With a catalyst, more collisions result in a reaction, so the rate of reaction increases.

Hope this helped :)

You might be interested in

What are other ways you can use wind energy to create electricity?

Phantasy [73]

You can use a fan on the wire. That's one way.

8 0

3 years ago

Read 2 more answers

Which trait will an organism that receives one dominant gene and one recessive gene most

serious [3.7K]

Answer: dominant

explanation: The dominant Gene wins because it overpowers the recessive gene.

4 0

3 years ago

Read 2 more answers

Match the alkane names and structures. -butane -methane -ethane -propane

SpyIntel [72]

Answer:

Explanation:

Here is the names and matches of butane methane ethane propane

7 0

3 years ago

Read 2 more answers

HURRY PLEASE!!

Alexandra [31]

From what i can gather it looks like d

5 0

3 years ago

Read 2 more answers

How many total atoms are in 0.290 g of P2O5?

Sliva [168]

There are 8.61 × 10²⁰ atoms in 0.290 g P₂O₅.

Step 1. Convert grams of P₂O₅ to moles of P₂O₅.

$\text{Moles of P}_{2}\text{O}_{5} = \text{0.290 g } \text{P}_{2}\text{O}_{5} \times \frac{\text{1 mol }\text{P}_{2}\text{O}_{5}}{\text{141.94 g }\text{P}_{2}\text{O}_{5}} = \text{0.002 043 mol } \text{P}_{2}\text{O}_{5} \\$

Step 2. Convert moles of P₂O₅ to molecules of P₂O₅.

$\text{Molecules of } \text{P}_{2}\text{O}_{5} = \text{0.002 043 mol } \text{P}_{2}\text{O}_{5} \times \frac{6.022 \times 10^{23}\text{ molecules }\text{P}_{2}\text{O}_{5}}{\text{1 mol } \text{P}_{2}\text{O}_{5}}\\$

$= 1.23 \times10^{21}\text{ molecules } \text{P}_{2}\text{O}_{5}\\$

Step 3. Convert molecules of P₂O₅ to atoms.

There are seven atoms in 1 mol P₂O₅.

∴ $\text{Total atoms} = 1.23\times 10^{21 }\text{ molecules }\text{P}_{2}\text{O}_{5} \times\frac{\text{7 atoms}}{\text{1 molecule }\text{P}_{2}\text{O}_{5}} = 8.61 \times 10^{21}\text{ atoms}\\$

8 0

3 years ago