Answer:
U = 80.91 J
Explanation:
In order to calculate the electric potential energy between the three charges you use the following formula:
(1)
k: Coulomb's constant = 8.98*10^9Nm^2/C^2
q1: q2 charge
r1,2: distance between charges 1 and 2.
For the three charges you have:
(2)
You use the fact that q1=q2=q3=q and that the distance between charges are equal. Then, in the equation (2) you have:
q = 1.45μC = 1.45*10^-6C
r = 0.700mm = 0.700*10^-3m

The electric potential energy between the three charges is 80.91 J
Explanation:
The given data is as follows.
F = 
q = 
v = 385 m/s
= 0.876
Now, we will calculate the magnitude of magnetic field as follows.
B = 
= 
=
T
= 10.65 T
Thus, we can conclude that magnitude of the magnetic field is 10.65 T.
Answer:
433 mph
Explanation:
We know that
...Eq(1)
Here,
Distance =1,592 miles
Time=3.68 hours
Putting the value of distance and Time in the Eq(1) We get
Velocity =

therefore Average velocity is 433 mph
Answer:
900
Explanation:
v = s / t = 9000m / 10 s = 900m/s