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1 year ago

A mole represents a macroscopic quantity of matter that can be used in the laboratory.

Chemistry

1 answer:

KonstantinChe [14]1 year ago

4 0

Answer:

A. True

Explanation:

Mole is the unit associated with measuring substances in chemistry. Chemicals are usually measured in moles and it is derived from the formula - mass/molar mass.

This makes the mole a definition of the representation of a macroscopic quantity of matter that can be used in the laboratory and hereby validates the answer as being true .

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How many atoms total are present in one molecule of 5-methyl-2 hexanol C7H16O

muminat

Answer:

24 atoms

Explanation:

The formula of the compound is C₇H₁₆O

The number of atoms that makes up one molecule of this compound are:

7 carbon atoms

16 hydrogen atoms

1 oxygen atom

The total number of atoms = 7+16+1 = 24 atoms

3 0

2 years ago

How many liters of a 6.0M solution Fe(SCN)2 are needed to prepare 2.0L of a 0.75M solution?

lubasha [3.4K]

Answer:

0.25L

Explanation:

Using the dilution formula

C1V1=C2V2

C1=6M

V1?

C2=0.75M

V2=2.0L

V1= C2V2/C1

V1=0.75*2.0/6

V1=0.25L

4 0

2 years ago

Read 2 more answers

Use the half-reaction method to balance the equation for the conversion of ethanol to acetic acid in acid solution:CH₃CH₂OH + Cr

garik1379 [7]

Balanced chemical equation is 3CH₃CH₂OH + 2Cr₂O₇²⁻ + 16H⁺ → 3CH₃COOH + 4Cr³⁺ + 11H₂O.

<h3>What is Balanced Chemical Equation ?</h3>

The balanced chemical equation is the equation in which the number of atoms on the reactant side is equal to the number of atoms on the product side in an equation.

The chemical equation

CH₃CH₂OH + Cr₂O₇²⁻ → CH₃COOH + Cr³⁺

First assign the oxidation number for each atom in the equation.

$\overset{+3}{C}\overset{+1}{H_3} \overset{-1}{C} \overset{+1}{H_2} \overset{-2}{O} \overset{+1}{H} + \overset{+6}{Cr_2} \overset{-2}{O_7} + \overset{+1}{H} \rightarrow \overset{+3}{C}\overset{+1}{H_3} \overset{+3}{C}\overset{-2}{O} \overset{-2}{O} \overset{+1}{H} + \overset{+3}{Cr}$

Oxidation: C₂H₆O → C₂H₄O₂ + 4e⁻

Reduction: Cr₂O₇ + 6e⁻ → 2Cr⁺³

Now, balance the charge

Oxidation: C₂H₆O → C₂H₄O₂ + 4e⁻ + 4H⁺

Reduction: Cr₂O₇ + 6e⁻ + 14H⁺ → 2Cr⁺³

Now balance the oxygen atoms

Oxidation: C₂H₆O + H₂O → C₂H₄O₂ + 4e⁻ + 4H⁺

Reduction: Cr₂O₇ + 6e⁻ + 14H⁺ → 2Cr⁺³ + 7H₂O

Now, make electron gain equivalent to lost

Oxidation: C₂H₆O + H₂O → C₂H₄O₂ + 4e⁻ + 4H⁺ } × 3

Reduction: Cr₂O₇ + 6e⁻ + 14H⁺ → 2Cr⁺³ + 7H₂O } × 2

Now,

Oxidation: 3C₂H₆O + 3H₂O → 3C₂H₄O₂ + 12e⁻ + 12H⁺

Reduction: 2Cr₂O₇ + 12e⁻ + 28H⁺ → 4Cr⁺³ + 14H₂O

Now, add the both equations

3CH₃CH₂OH + 2Cr₂O₇²⁻ + 16H⁺ → 3CH₃COOH + 4Cr³⁺ + 11H₂O

Thus from the above conclusion we can say that the balanced chemical equation is 3CH₃CH₂OH + 2Cr₂O₇²⁻ + 16H⁺ → 3CH₃COOH + 4Cr³⁺ + 11H₂O.

Learn more about the Balanced chemical equation here: brainly.com/question/26694427

#SPJ4

7 0

8 months ago

Which of the following statements is false concerning the formula of a compound?

aalyn [17]

Answer:

B. The number of atoms in a molecular formula is always greater than the number of atoms in an empirical formula.

Explanation:

It is not always true that the number of atoms in a molecular formula is always greater than the number of atoms in an empirical formula.

The chemical formulae of a compound are of two main types;

The empirical formula is that which expresses the composition of a compound in the simplest whole number ratio.
The molecular formula shows the actual ratio of the atoms in a compound.

Sometimes the number of atoms in the molecular and empirical formula can be the same.

Also, the number of atoms in the molecular formula is always greater than that of the empirical formula when they are not the same.

3 0

2 years ago

A chemist needs to make 250 mL of a 2.50 M aqueous solution of ammonium hydroxide from a 6.00 M ammonium hydroxide solution. How

Furkat [3]

Answer:

250 mL (total solution) = 104 mL (stock solution) + 146 mL (water)

Explanation:

Data Given

M1 = 6.00 M

M2 = 2.5 M

V1 = 250 mL

V2 = ?

Solution:

As the chemist needs to prepare 250 mL of solution from 6.00 M ammonium hydroxide solution to prepare a 2.50 M aqueous solution of ammonium hydroxide.

Now

first he have to determine the amount of ammonium hydroxide solution that will be taken from6.00 M ammonium hydroxide solution

For this Purpose we use the following formula

M1V1=M2V2

Put values from given data in the formula

6 x V1 = 2.5 x 250

Rearrange the equation

V1 = 2.5 x 250 /6

V1 = 104 mL

So 104 mL is the volume of the solution which we have to take from the 6.00 M ammonium hydroxide solution to prepare 2.5 M aqueous solution of ammonium hydroxide

But we have to prepare 250 mL of the solution.

so the chemist will take 104 mL from 6.00 M ammonium hydroxide solution and have to add 146 mL water to make 250 mL of new solution.

in this question you have to tell about the amount of water that is 146 mL

250 mL (total solution) = 104 mL (stock solution) + 146 mL (water)

7 0

2 years ago