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GREYUIT [131]
2 years ago
9

An electric model train is accelerated at a rate of 8 m/s^2 by a 12 N force? What is the

Physics
1 answer:
jok3333 [9.3K]2 years ago
4 0

Answer:

m = 1.5 kg

Explanation:

Data:

  • Aceleration (a) = 8 m/s²
  • Force (F) = 12 N
  • Mass (m) = ?

Use formula:

  • \boxed{m = \frac{F}{a}}

Replace in the formula:

  • \boxed{m = \frac{12N}{8\frac{m}{s^{2}}}}

Equate the newtons:

  • \boxed{m = \frac{12kg*\frac{m}{s^{2}}}{8\frac{m}{s^{2}}}}

Simplify m/s²:

  • \boxed{m = \frac{12kg}{8}}

It divides:

  • \boxed{m =1.5kg}

What is the mass of the train?

The mass of the train is <u>1.5 kilograms.</u>

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A grapefruit falls from a tree and hits the ground 0.76 s later.
Tomtit [17]

Answer:

2.8 m 7.4 m/s

Explanation:

write all the values then use the equations of motion to find the distance and speed. please see attached photo

7 0
3 years ago
Which wavelength produces fluorescence? Why do you think this wavelength produces fluorescence while the other does not?
Maurinko [17]

Answer:

Long wavelength

Explanation:

Wavelengths that corresponds to the bands of blue and red are strongly absorbed whereas the wavelengths that lie in the mid-range corresponds to green light that are absorbed weakly.

Fluorescence produced is always directed towards longer wavelengths of the spectra as compared to the corresponding spectra for absorption.

4 0
2 years ago
Which of these best describes heat? total thermal energy degree of warmth transfer of thermal energy average kinetic energy
Papessa [141]

Total thermal energy is the answer to your question.

3 0
2 years ago
an object is acted on by a drag force with a magnitude that is proportional to the speed. the object accelerates downward at 3.0
Nutka1998 [239]

The terminal speed of the object falling down is 66.67 m/s.

The terminal speed acquired by the body when,

Weight of the body = Drag force of the body

It is given,

Drag force is directly proportional to the speed,

So,

F = CV

Where F is drag force,

V is the speed,

C is the constant,

So, it can be written as C = F/V.

The weight of the body = mg

The weight of the body = 10m

M is the mass and g is the acceleration due to gravity,

The drag force when the speed is 20m/s.

Drag force = ma

a is the acceleration during the drag force which is given to be 3m/s²,

Drag force = 3m

Now we can write,

F₁/V₁ = F₂/V₂

F₁ is the drag force at 20m/s speed.

F₂ is the weight of the body and V₂ is the terminal speed,

Now, it can be written,

3m/20 = 10m/V₂

V₂ = 66.67 m/s.

So, the terminal speed is 66.67m/s.

To know more about terminal speed, visit,

brainly.com/question/14605362

#SPJ4

7 0
1 year ago
One knife is longer from the cutting edge to the back of the blade. It's easier to push the longer knife through a pear and more
AlladinOne [14]

By the formula of torque balance we know that

\tau = r\times F

here we know that

r = distance of force

F = applied force

so here we know that as we will take large edge knife then the distance of force will increase

due to this the torque will also increase in it so it is easy to pear it

So here we can say

F_{in}r_1 = F_{out}r_2

F_{out} = \frac{r_1}{r_2} F_{in}

so output force will increase in this case

So here the correct answer would be

<em>b. the longer the knife, the stronger the output force</em>

6 0
3 years ago
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