What happens as photons of visible light are absorbed by dye molecules?
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Question is incomplete. Missing part:
Find the charge on the capacitor at the following times:
1) t = 0 mu S
2) t = 1 mu S
3) t = 50 mu S
1)
We start by calculating the initial charge on the capacitor. For this, we can use the following relationship:
where
C is the capacitance
Q0 is the initial charge stored
V0 is the initial potential difference across the capacitor
When the capacitor is connected to the battery, we have:
Solving for ,
So, when the battery is disconnected, this is the charge on the capacitor at time t = 0.
2)
To find the charge on the capacitor at any other time t, we use the equation:
where
t is the time
is the resistance
is the capacitance
Therefore, at time , we have:
3)
As before, we use again the equation:
However, here the time to consider is
Substituting into the formula,