Explanation:
It is given that,
length of steel wire, l = 0.75 m
Mass of the wire, m = 12 g = 0.012 kg
Fundamental frequency, f = 120 Hz
We need to find the mass of the anvil (m'). The fundamental frequency is given by :

v is the speed of the mass
Speed is given by :

is the mass per unit length,

T is the tension in the wire,



T = 518.4 N
Tension in the wire, T = m' g


m' = 52.89 kg
So, the mass of the anvil is 52.89 kg. Hence, this is the required solution.