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Ludmilka [50]
3 years ago
13

The drawing on the right shows a man (mass = 70kg) and the child (mass = 35 kg) push each other apart. The man moves away with a

speed of 0.3 m/s relative to the ice.
Calculate the velocity of the child relative to the ice.


LET MOMENTUM EQUATION GUIDE YOUR THINKING...


SHOW YOUR WORK - INCLUDE UNITS

Physics
2 answers:
nordsb [41]3 years ago
7 0

Refer to the attachment..

Pepsi [2]3 years ago
3 0

Answer:

<h2>Hope it would help you.</h2>

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A baby carriage is sitting at the top of a hill that is 21m high. The carriage with the baby weighs 12 n. What's the potential e
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A baby carriage is sitting at the top of a hill that is 21m high. The carriage with the baby weighs 12N. The carriage has... energy. Calculate it = <span>252J</span>
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3 years ago
Find the equivalent resistance.
frosja888 [35]

Answer:

18 Ω

Explanation:

As K and F are at the same voltage, we can redraw the diagram as in figure 2

Series resistances add directly, so we get figure 3

Adding parallel resistances gets us to figure 4

Now we can move two 6Ω resistances for clarification in figure 5

As the voltage between C and J will be identically split between D and H, there will be no voltage drop across the middle 6Ω resister and no current through it, identical to an infinite resistance, so that 6Ω can be eliminated as in figure 6

Add series resistances to get to figure 7

Add parallel resistances to get to figure 8

Add series resistances to get to figure 9

6 0
3 years ago
Read 2 more answers
A uniform rod of length L rests on a frictionless horizontal surface. The rod pivots about a fixed frictionless axis at one end.
Svet_ta [14]

Answer: a) 0.315 (V/L)

Explanation:

From Conservation of angular momentum, we know that

L1 = L2 ,

Therefore MV L/2 = ( Irod + Ib) x W

M/4 x V x L/2 = (M (L/2)^2 + 1/3xMxL^2) x W

M/8 X VL = (ML^2/16 + ML^2 /3 )

After elimination we have,

V/8 = 19/48 x L x W

W = 48/8 x V/19L = 6/19 x V/L

Therefore W = (0.136)X V/L

6 0
3 years ago
he capacitor can withstand a peak voltage of 550 VV . If the voltage source operates at the resonance frequency, what maximum vo
anygoal [31]

Answer:

The maximum voltage is 39.08 V.

Explanation:

Given that,

Voltage = 550 V

Suppose, In an L-R-C series circuit, the resistance is 400 ohms, the inductance is 0.380 Henry, and the capacitance is 1.20\times10^{-2}\mu F

We need to calculate the resonant frequency

Using formula of resonant frequency

f=\dfrac{1}{2\pi\sqrt{LC}}

Put the value into the formula

f=\dfrac{1}{2\pi\sqrt{0.380\times1.20\times10^{-8}}}

f=2356.8\ Hz

We need to calculate the maximum current

Using formula of current

I=\dfrac{V_{c}}{X_{c}}

I=2\pi f C\times V_{c}

Put the value into the formula

I=2\pi\times2356.8\times1.20\times10^{-8}\times550

I=0.0977\ A

We need to calculate the impedance of the circuit

Using formula of impedance

Z=\sqrt{R^2+(X_{L}-X_{C})^2}

At resonant frequency , X_{L}=X_{C}

So, Z = R

We need to calculate the maximum voltage

Using formula of voltage

V=IR

Put the value into the formula

V=0.0977\times400

V=39.08\ V

Hence, The maximum voltage is 39.08 V.

4 0
4 years ago
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