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3 years ago

Which criteria are responsible for deciding whether a heterogeneous mixture is a colloid or a suspension?

2 answers:

8 0

I think the correct answer is the second option. The criteria that are responsible for deciding whether a heterogeneous mixture is a colloid or a suspension would be whether the particles remain suspended for an extended period of time

Ugo [173]3 years ago

5 0

Answer:

The correct answer is that whether it can be separated into simpler substances via physical separation procedures.

Explanation:

A mixture, which is not uniform in the composition is known as a heterogeneous mixture. The examples of heterogeneous mixtures are colloids and suspension. In suspensions, the components get distinguished itself through simple physical separation techniques, while in colloids the constituents do not get distinguished as the colloids prevail in liquid, solid, or gaseous state.

If a suspension is permitted to stand the particles will get distinguish. A colloid is an intermediate between a suspension and a solution. A suspension will separate out, however, a colloid will not.

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Which atom is most likely to attract electrons in a bond? A) K B) Na C) S D) Se

jeka57 [31]

C) S

Because of the trends of electronegativity. Increases across a period and decreases down a group.

4 0

3 years ago

What is the density of lead (in g/cm^3 3 ) if a rectangular bar measuring 0.500 cm in height, 1.55 cm in width, and 25.00 cm in

Viktor [21]

Answer:

Density = 11.4 g/cm³

Explanation:

Given data:

Density of lead = ?

Height of lead bar = 0.500 cm

Width of lead bar = 1.55 cm

Length of lead bar = 25.00 cm

Mass of lead bar = 220.9 g

Solution:

Density = mass/ volume

Volume of bar = length × width × height

Volume of bar = 25.00 cm × 1.55 cm × 0.500 cm

Volume of bar = 19.4 cm³

Density of bar:

Density = 220.9 g/ 19.4 cm³

Density = 11.4 g/cm³

3 0

3 years ago

Procaine hydrochloride ( MW = 272.77 g/mol) is used as a local anesthetic. Calculate the molarity of a 4.666 m solution which ha

fenix001 [56]

Answer:

$\boxed{\text{2.274 mol/L}}$

Explanation:

$b = \dfrac{\text{moles of solute}}{\text{kilograms of solvent}}$

Assume 1 kg water.

1. Moles of P.HCl

Then we have 4.666 mol of P.HCl

2. Mass of P.HCl

n = 4.666 mol × 272.77 g/mol = 1271.1 g

3. Total mass of solution

m = 1000 g + 1271.1 g = 2271.1 g solution

4. Volume of solution

$V = \text{2271.1 g} \times \dfrac{\text{1 mL}}{\text{1.1066 g}} = \text{2052.3 mL} = \text{2.0523 L}$

5. Molar concentration

$\begin{array}{rcl}c & = & \dfrac{\text{moles of solute}}{\text{litres of solution}}\\\\c & = & \dfrac{\text{4.666 mol}}{\text{2.0523 L}}\\\\ & = & \text{2.274 mol/L}\\\end{array}\\$