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3 years ago

Which criteria are responsible for deciding whether a heterogeneous mixture is a colloid or a suspension?

2 answers:

8 0

I think the correct answer is the second option. The criteria that are responsible for deciding whether a heterogeneous mixture is a colloid or a suspension would be <span>whether the particles remain suspended for an extended period of time</span>

Ugo [173]3 years ago

5 0

Answer:

The correct answer is that whether it can be separated into simpler substances via physical separation procedures.

Explanation:

A mixture, which is not uniform in the composition is known as a heterogeneous mixture. The examples of heterogeneous mixtures are colloids and suspension. In suspensions, the components get distinguished itself through simple physical separation techniques, while in colloids the constituents do not get distinguished as the colloids prevail in liquid, solid, or gaseous state.

If a suspension is permitted to stand the particles will get distinguish. A colloid is an intermediate between a suspension and a solution. A suspension will separate out, however, a colloid will not.

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4 years ago

Carry out the following calculation, paying special attention to the significant figures (where 4/3 is exact), rounding, and uni

babunello [35]

Answer:

Value = 1.80 g/cm³ (Approx)

Explanation:

Given:

$\frac{3.39 \times 10^7g}{(\frac{4}{3} )(3.1416)(1.65 \times 10^2 cm)^3}$

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$\frac{3.39 \times 10^7g}{(\frac{4}{3} )(3.1416)(1.65 \times 10^2 cm)^3} \\\\\frac{3.39 \times 10^7g}{(\frac{4}{3} )(3.1416)(4.492125 \times 10^6 cm^3)} \\\\ \frac{3.39 \times 10^7g}{(\frac{4}{3} )(3.1416)(4.492125 \times 10^6 cm^3)}\\\\ \frac{3.39 \times 10^7g}{18.8166132\times 10^6 cm^3} \\\\ 1.80159945g/cm^3$

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7 0

4 years ago

Calculate the density of the aluminum cylinder with a diameter 0f 1.3 cm weighing 18 grams. Height of the cylinder is 5.2 Cm. Fi

Masja [62]

Answer:

Percent error = 3.7%

Explanation:

Given data:

Density of Al cylinder = ?

Weight of cylinder = 18 g

Diameter = 1.3 cm

Height = 5.2 cm

Actual density of Al = 2.7 g/cm³

Percent error = ?

Solution:

First of all we will calculate the volume of cylinder through given formula.

V = πr²h

r = diameter /2

V = 22/7 × (0.65 cm)²× 5.2 cm

V = 22/7 × 0.4225cm²× 5.2 cm

V = 6.89 cm³

Now we will calculate the density.

d = m/v

d = 18 g/ 6.89 cm³

d = 2.6 g/cm³

Percent error:

Percent error = measured value - actual value /actual value × 100

Percent error = 2.6g/cm³ - 2.7g/cm³ /2.7g/cm³ × 100

Percent error = 3.7%

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3 years ago

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4 years ago

Read 2 more answers

Which criteria are responsible for deciding whether a heterogeneous mixture is a colloid or a suspension?﻿

Which criteria are responsible for deciding whether a heterogeneous mixture is a colloid or a suspension?