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Deffense [45]
3 years ago
9

Pleas ehelp about convergent boundaries and don't spam I really need help on a few question PLLLLLLZZZ

Physics
2 answers:
Lapatulllka [165]3 years ago
8 0
I Don’t know I’m so sorry
ratelena [41]3 years ago
4 0
The top paragraph explains it all. The plates are moving because of the directing the force is creating, a check next to both blocks I’m not good in explaining sorry.
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OleMash [197]
That's not true people that have a broken leg use crutches and the constant lifting of their own body weight will help them gain muscle 
8 0
4 years ago
40 POINTS
goldenfox [79]

Answer:

<em>Well, I think the best answer will be is </em><em>B) Gravity. Good luck!</em>

5 0
3 years ago
Read 2 more answers
The electric flux through a square-shaped area of side 5 cm near a very large, thin, uniformly-charged sheet is found to be 3\ti
deff fn [24]

Answer:

Explanation:

Given

side of square shape a=5\ cm

Electric flux \phi =3\times 10^{-5}\ N.m^2/C

Permittivity of free space \epsilon_0=8.85\times 10^{-12} \frac{C^2}{N.m^2}

Flux is given by

\phi =EA\cos \theta

where E=electric field strength

A=area

\theta=Angle between Electric field and area vector

E=\frac{\phi }{A\cos (0)}

E=\frac{3\times 10^{-5}}{25\times 10^{-4}\times \cos(0)}

E=0.012\ N/C

and Electric field  by a uniformly charged sheet is given by

E=\frac{\sigma }{2\epsilon_0}

where \sigma=charge density

=\frac{\sigma }{\epsilon_0}

\sigma =0.012\times 8.85\times 10^{-12}

\sigma =2.12\times 10^{-13}\ C/m^2    

5 0
3 years ago
Why evaporation are called surface phenomenon?
Eva8 [605]
The water formed on the surface of the water evaporation loss (evaporation), consisting of plant transpiration water loss (transpiration) is called. Soil near the plant and the resulting water loss is called by evapotranspiration.
6 0
4 years ago
Read 2 more answers
What decibel reading corresponds to a pressure amplitude of 0.2 W/m^2?
horsena [70]

I  = pressure amplitude given = 0.2 W/m²

dB = decibel reading

decibel reading from the pressure amplitude is given as

dB = 10 log₁₀ (I/10⁻¹²)

inserting the values in the above equation

dB = 10 log₁₀ (0.2/10⁻¹²)

dB = 10 log₁₀ (2 x 10⁻¹/10⁻¹²)

dB = 10 log₁₀ (2 x 10⁻¹.10¹²)

dB = 10 log₁₀ (2 x 10¹²⁻¹)

dB = 10 log₁₀ (2 x 10¹¹)

dB = 113.01 db

hence the decibel reading comes out to be 113.01 db


4 0
3 years ago
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