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andre [41]
3 years ago
11

A reconnaissance plane flies 556 km away from

Physics
1 answer:
9966 [12]3 years ago
5 0

We use the formula, to calculate the average speed of the round trip,

v_{av} =\frac{d_{total}}{t_{total}}

Here, d_{total}, is total distance covered by plane in total time, t_{total}.

For the round trip,

d_{total=556\ km+556\ km=1112 \times 10^3\ m

t_{total}=\frac{556 \times 10^3 m}{832 m/s} + \frac{556 \times 10^3 m}{1248 m/s}.

Thus,

v_{av} =\frac{1112 \times 10^3\ m}{\frac{556 \times 10^3 m}{832 m/s} + \frac{556 \times 10^3 m}{1248 m/s}} =\frac{1112 \times 10^3\ m}{668.26\ s+445.51\s} \\\\v_{av}=998.41\ m/s.


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3 years ago
Canadian Olivia Oliver broke the Guinness World Record for the fastest spin on ice skates on January 2015 with an angular veloci
Shalnov [3]

Answer:

<em>a) 2.63 : 1</em>

<em>b) 143.13 rpm</em>

Explanation:

initial angular velocity ω' = 130 rpm

final angular velocity ω = 342 rpm

recall that angular momentum = ωI

where I is the moment of inertia.

for the initial spinning condition, we take moment of inertial = I'

for final spinning condition, we take moment of inertia = I

initial angular momentum = ω'I' = 130 I'

final angular momentum = ωI = 342 I

according to conservation of angular momentum, initial angular momentum must be equal to the final angular momentum, therefore

342 I = 130 I'

ratio of initial moment of inertia to final moment of inertia = I'/I

==> I'/I = 342/130 ≅ <em>2.63 : 1</em>

b) to achieve a final angular velocity of of 375 rpm, her initial velocity will have to be

2.63 = 375/ω'

ω' = 375/2.63 = <em>143.13 rpm</em>

6 0
3 years ago
A tiger runs one kilometer. The tiger does 15,000 J of work and has a total power output of 500 W. How many minutes does it take
defon
Power is the amount of energy consumed per unit time. Having no direction, it is a scalar quantity. <span>As is implied by the equation for </span>power<span>, a unit of </span>power <span>is equivalent to a unit of work divided by a unit of time. The formula would be as follows:

P = W/t 

We calculate as follows:

500 W = 15000 J / t
t = 30 s</span>
3 0
3 years ago
A 51-kg packing crate is pulled with constant speed across a rough floor with a rope that is at an angle of 37.0° above the hor
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work is done by the pulling force which is same as the tension force in the rope. the net work done is zero for the crate since crate moves at constant velocity. but there is work done by the tension force which is equal in magnitude to the work done by the frictional force.

T = tension force in the rope = 115 N

d = displacement of the crate = 7.0 m

θ = angle between the direction of tension force and displacement = 37 deg

work done on the crate is given as

W = F d Cosθ

inserting the values given above

W = (115) (7.0) Cos37

W = 643 J

3 0
3 years ago
A boy runs 125 meters north, and the. 75 meters south
AveGali [126]

Answer:

50 meters

Explanation:

50 meters

50 meters

8 0
3 years ago
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