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alexandr1967 [171]
3 years ago
5

Driving to the city, at one point the vehicle you were in, was moving at 80 mph, how fast is it in km/h?

Engineering
2 answers:
mars1129 [50]3 years ago
5 0

Answer:

128.74 Km/h

Explanation:

salantis [7]3 years ago
4 0
The answer is 128.74km
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Air enters a compressor operating at steady state at 1.05 bar, 300 K, with a volumetric flow rate of "84" m3/min and exits at 12
Nina [5.8K]

Answer:

W = - 184.8 kW

Explanation:

Given data:

P_1 = 1.05 bar

T_1 = 300K

\dot V_1 = 84 m^3/min

P_2 = 12 bar

T_2 = 400 K

We know that work is done as

W = - [ Q + \dor m[h_2 - h_1]]

forP_1 = 1.05 bar,  T_1 = 300K

density of air is 1.22 kg/m^3 and h_1 = 300 kJ/kg

for P_2 = 12 bar, T_2 = 400 K

h_2 = 400 kj/kg

\dot m = \rho \times \dor v_1 = 1.22 \frac{84}{60} =1.708 kg/s

W = -[14 + 1.708[400-300]]

W = - 184.8 kW

8 0
3 years ago
An inventor claims to have developed a refrigerator that at steady state requires a net power input of 1.1 horsepower to remove
Lynna [10]

Answer:

The inventor's claim is false in the sense that no thermal machine can violate the first thermodynamic law.

Explanation:

The inventor's claim could not be possible as no thermal machine can transfer more heat than the input work consumed. If we expose the thermal efficiency:

n=Q out / W in

Where Q and W both must be in the same power unit, so we will convert the remove heat from BTU/hr to hp:

12000 BTU/hr = 4.72 hp

Therefore by comparing, we notice that the removing heat of 4.75 hp is large than the delivered work of 1.11 hp. By evaluating the efficiency:

[tex]n=4.75 hp / 1.1 hp  = 4.3 > 1[/tex]

6 0
3 years ago
Which test element is used to apply test execution settings for the main business flow excluding Login and Log out 1) Run time c
Svet_ta [14]

Test element is used to apply test execution settings for the main business flow excluding Login and Log out is "Transaction  controller"

<u>Explanation:</u>

Transaction controllers are a technoscientifically kind of controllers that produce an additional sample that measures the overall time is taken or response time to perform its nested samplers.

The Controller has two checkboxes,those are

1.Generate Parent Samples

2. Include term of the timer and pre-post processors in the produced sample - It is the time which involves all processing samples within the Transaction controller, not just the HTTP samples. In Case one sample is lost or crashed then the entire Transaction Controller will fail. In case anyone sample assertion is failed then the complete Transaction Controller will fail.

3 0
4 years ago
In some states, repair shops can accept used oil from do-it-yourselfers or ____________.
MrMuchimi

Answer:

C. Homeowners

Explanation:

I just took my automotive pollution prevention certification and passed by answering homeowners for this question.

7 0
3 years ago
Air at 7 deg Celcius enters a turbojet engine at a rate of 16 kg/s and at a velocity of 300 m/s (relative to engine). Air is hea
Savatey [412]

To solve this problem we will start using the given temperature values and then transform them to the Kelvin scale. From there through the properties of the tables, described for the Air, we will find the entropy. With these three data we can perform energy balance and find the speed of the fluid at the exit, which will finally help us find the total force:

V_i = 300m/s

T_1 = 7\°C = 280K

T_2 = 427\°C = 700K

\dot{m} 16kg/s

\dot{Q}_{in} = 15000kJ/s

Using the tables for gas properties of air we can find the enthalpy in this two states, then

T_1 = 280K \rightarrow h_1 = 280.13kJ/Kg\cdot K

T_2 = 700K \rightarrow h_2 = 713.27kJ/Kg\cdot K

Applying energy equation to the entire engine we have that

\frac{\dot{Q}_{in}}{\dot{m}}+h_1 +\frac{1}{2} V^2_{in} = h_2 + \frac{1}{2} V^2_{out}

\frac{15000}{16}*10^3+280.13*10^3+\frac{1}{2} 300^2 = 713.27*10^3+\frac{1}{2} V^2_{out}

V_{out} = 1048.198m/s

Finally the force in terms of mass flow and velocity is

F = \dot{m} (V_{out}-V_{in})

F = 16(1048.198-300)

F= 11971.168N

Therefore the thrust produced by this turbojet engine is  11971.168N

4 0
3 years ago
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