Answer:
W = - 184.8 kW
Explanation:
Given data:





We know that work is done as
![W = - [ Q + \dor m[h_2 - h_1]]](https://tex.z-dn.net/?f=W%20%3D%20-%20%5B%20Q%20%2B%20%5Cdor%20m%5Bh_2%20-%20h_1%5D%5D)
for
density of air is 1.22 kg/m^3 and 
for 


W = -[14 + 1.708[400-300]]
W = - 184.8 kW
Answer:
The inventor's claim is false in the sense that no thermal machine can violate the first thermodynamic law.
Explanation:
The inventor's claim could not be possible as no thermal machine can transfer more heat than the input work consumed. If we expose the thermal efficiency:
Where Q and W both must be in the same power unit, so we will convert the remove heat from BTU/hr to hp:
Therefore by comparing, we notice that the removing heat of 4.75 hp is large than the delivered work of 1.11 hp. By evaluating the efficiency:
[tex]n=4.75 hp / 1.1 hp = 4.3 > 1[/tex]
Test element is used to apply test execution settings for the main business flow excluding Login and Log out is "Transaction controller"
<u>Explanation:</u>
Transaction controllers are a technoscientifically kind of controllers that produce an additional sample that measures the overall time is taken or response time to perform its nested samplers.
The Controller has two checkboxes,those are
1.Generate Parent Samples
2. Include term of the timer and pre-post processors in the produced sample - It is the time which involves all processing samples within the Transaction controller, not just the HTTP samples. In Case one sample is lost or crashed then the entire Transaction Controller will fail. In case anyone sample assertion is failed then the complete Transaction Controller will fail.
Answer:
C. Homeowners
Explanation:
I just took my automotive pollution prevention certification and passed by answering homeowners for this question.
To solve this problem we will start using the given temperature values and then transform them to the Kelvin scale. From there through the properties of the tables, described for the Air, we will find the entropy. With these three data we can perform energy balance and find the speed of the fluid at the exit, which will finally help us find the total force:





Using the tables for gas properties of air we can find the enthalpy in this two states, then


Applying energy equation to the entire engine we have that



Finally the force in terms of mass flow and velocity is



Therefore the thrust produced by this turbojet engine is 11971.168N