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STALIN [3.7K]
3 years ago
13

Pls help me 6th grade science second two pics are the possible answers

Physics
1 answer:
vladimir2022 [97]3 years ago
3 0

Answer:

C

Explanation:

Plotting the data points would get the graph closest to C

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Guy can someone help me with this
Mrac [35]

I believe it should be B.

Here’s one desctiption:

When the balloon has been rubbed enough times to gain a sufficient negative charge, it will be attracted to the wall. Although the wall should normally have a neutral charge, the charges within it can rearrange so that a positively charged area attracts the negatively charged balloon

Hopefully it’s right!

3 0
3 years ago
An object is thrown vertically upward with an initial velocity of 50 m/s. Find
Gwar [14]
The answers B because your doing m/s
6 0
3 years ago
A ball with a mass of 160 g which contains 4.40×108 excess electrons is dropped into a vertical shaft with a height of 115 m . A
faltersainse [42]

Answer:

F= 6.69*10^{-10}N

Explanation:

To find the force we proceed by defining the variables we have,

m= 160g\\n= 4.40*10^8\\h=115m\\B=0.2T\\e= 1.602*10^{-19}c

The charge on one of the balls is defined under the equation,

q=ne

q= 4.40*10^8(1.602*10^{-19}c)

q= 7.0488*10^{-11}

Due to the height we need to calculate the potential energy at the height of 115m,

PE=mgh

The kinetic energy would be given by

KE= \frac{1}{2}mv^2

From the law of conservation we equate the two equations

\frac{1}{2}mv^2=mgh

v=\sqrt{2gh}

v=\sqrt{2(9.8)(115)}

v= 47.47m/s

In this way we now calculate the strength of the particle

F=qVB

F= (7.0488*10^{-11})(47.47)(0.2)

F= 6.69*10^{-10}N

8 0
3 years ago
A gasoline engine absorbs 2 500 J of heat and performs 1 000 J of mechanical work in each cycle. The efficiency of the engine is
larisa86 [58]

Answer:

The efficiency of the engine is 40 %

Explanation:

Given;

input energy, = 2500 J

output energy, = 1000 J

The efficiency of the engine is given as;

Efficiency = output energy / input energy

Efficiency = 1000 / 2500

Efficiency = 0.4

Efficiency(%) = 0.4 x 100%

Efficiency = 40 %

Therefore, the efficiency of the engine is 40 %

5 0
3 years ago
A parallel-plate capacitor is charged and then is disconnected from the battery. By what factor does the stored energy change wh
andrew-mc [135]

Answer:

0.5

Explanation:

The energy of a charged capacitor is given by \frac{1}{2}QC where Q is the charge on it and C is its capacitance. The capacitance is defined, geometrically, as

\dfrac{\epsilon A}{d}

where \epsilon is a constant that is determined by the material between the plates, A is the area of the plates and d is the distance between them. It is then that the capacitance is linearly inversely proportional to the separation distance; as the distance increases, the capacitance reduces.

Because it is linear, when the separation distance is doubled, other factors remaining constant, the capacitance is halved. Because the capacitance is halved, the energy is halved.

Let's see the mathematics.

Initial capacitance, C_1 at initial separation, d_1

C_1=\dfrac{\epsilon A}{d_1}

If separation is doubled, separation becomes d_2=2d_1. Then the capacitance becomes

C_2=\dfrac{\epsilon A}{d_2}

C_2=\dfrac{\epsilon A}{2d_1}

C_2=0.5\dfrac{\epsilon A}{d_1}

C_2=0.5C_1

Initial energy, E_1=\frac{1}{2}QC_1

Final energy, E_2=\frac{1}{2}QC_2= \frac{1}{2}Q\times0.5C_1

E_2=0.5\times\frac{1}{2}QC_1=0.5E_1

Hence, \frac{E_2}{E_1}=0.5

5 0
3 years ago
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