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Step2247 [10]
3 years ago
8

Which beaker contain elements?

Chemistry
2 answers:
dimulka [17.4K]3 years ago
7 0

Answer:

all

Explanation:

and if we are being posific its C i think

Mnenie [13.5K]3 years ago
7 0

Answer: The correct answer is : option A. Beakers A and B contain an equal number of atoms.

Explanation:

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You water three sunflower plants with salt water. Each plant receives a different concentration of salt solutions. A fourth plan
quester [9]

Answer:

Please please please mark me brainlest!

Explanation:

IV: salt solution

DV: Hight of plants

Control: the fourth plant

Independent Variable: what it's watered with (regular water or salt water as well as the concentration of salt water)

Dependent Variable: Height

Control: the type of plant (sunflower) Hope this helps you! Ask me anything if you have any quistions!

8 0
3 years ago
What is the defination of epsom salt?
prisoha [69]
Crystals of hydrated magnesium sulfate used as a purgative or for other medicinal use


It on googIe
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7 0
2 years ago
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Balance the chemical equation below using the smallest possible whole number stoichiometric coefficients.
pogonyaev
I think it's balanced ?
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And one P in the both side
7 0
1 year ago
Write the complete atomic structure for the Carbon atom. The atomic and mass numbers for carbon are 6 and 12 reapectively.​
sergiy2304 [10]

Answer:

C-12 or C with a 12 superscripted on Upper left and 6 Subscripted on bottom left

Explanation:

Isotopic notation

4 0
2 years ago
How many moles are in 39.5 grams of Lithium?
Blizzard [7]

Answer:

185.05 g.

Explanation

Firstly, It is considered as a stichiometry problem.

From the balanced equation: 2LiCl → 2Li + Cl₂

It is clear that the stichiometry shows that 2.0 moles of LiCl is decomposed to give 2.0 moles of Li metal and 1.0 moles of Cl₂, which means that the molar ratio of LiCl : Li is (1.0 : 1.0) ratio.

We must convert the grams of Li metal (30.3 g) to moles (n = mass/atomic mass), atomic mass of Li = 6.941 g/mole.

n = (30.3 g) / (6.941 g/mole) = 4.365 moles.

Now, we can get the number of moles of LiCl that is needed to produce 4.365 moles of Li metal.

Using cross multiplication:

2.0 moles of LiCl → 2.0 moles of Li, from the stichiometry of the balanced equation.

??? moles of LiCl → 4.365  moles of Li.

The number of moles of LiCl that will produce 4.365 moles of Li (30.3 g) is (2.0 x 4.365 / 2.0) = 4.365 moles.

Finally, we should convert the number of moles of LiCl into grams (n = mass/molar mass).

Molar mass of LiCl = 42.394 g/mole.

mass = n x molar mass = (4.365 x 42.394) = 185.05 g.

7 0
2 years ago
Read 2 more answers
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