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Virty [35]
3 years ago
5

Please help!!!!!!!! 25 points

Physics
2 answers:
Archy [21]3 years ago
7 0

Answer:

B: beaks, finches.

Explanation:

Beaks, finches. This is because he noticed that fruit-eating finches had beaks similar to parrots, while finches that ate insects had narrow beaks. The difference in their beaks is due to adapting to different environments which causes them to evolve into different species of finches.

andrezito [222]3 years ago
7 0
The answer is B !

Dhhdbdndn
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The indices of refraction for violet light (λ = 400 nm) and red light (λ = 700 nm) in diamond are 2.46 and 2.41, respectively. A
JulijaS [17]

Answer:

0.42°

Explanation:

Using Snell's law of refraction which states that the ratio of the angle of sin of incidence to angle of sine of refraction is equal to a constant for a given pair of media. Mathematically,

Sin(i)/sin(r) = n

n is the refractive index of the medium

FOR VIOLET LIGHT:

n = 2.46

i = 51°

r = ?

To get r, we will use the Snell's law formula.

2.46 = sin51°/sinr

Sinr = sin51°/2.46

Sinr = 0.316

r = sin^-1(0.316)

rv = 18.42°

FOR RED LIGHT:

n = 2.41

i = 51°

r = ?

To get r, we will use the Snell's law formula.

2.41 = sin51°/sinr

Sinr = sin51°/2.41

Sinr = 0.323

r = sin^-1(0.323)

rd = 18.84°

The angular separation between these two colors of light in the refracted ray will be the difference between there angle of refraction.

Angular separation = rd - rv

= 18.84° - 18.42°

= 0.42°

6 0
3 years ago
Is there life on other planets ?
RUDIKE [14]
Supposedly there is life on Mars but it’s early to say for sure
7 0
3 years ago
Read 2 more answers
Galilee said that if you rolled a ball along a level surface it would be
lana [24]
The answer would be stay because the surface is flat so it will stay!
3 0
3 years ago
A force of 8.0 N is along x direction, another force of 6.0 N is along +y direction. If both forces are acting on a point object
Darya [45]

Answer:

Resultant force, R = 10 N

Explanation:

It is given that,

Force acting along +x direction, F_x=8\ N

Force acting along +y direction, F_y=6\ N

Both the forces are acting on a point object located at the origin. Let the resultant force of the object is given by R. So,

R=\sqrt{F_x^2+F_y^2+F_xF_y\ cos\theta}

Here \theta=90^{\circ}

R=\sqrt{F_x^2+F_y^2}

R=\sqrt{8^2+6^2}

R = 10 N

So, the resultant force on the object is 10 N. Hence, this is the required solution.

6 0
3 years ago
The height of a projectile t seconds after it is launched straight up in the air is given by f (t )equals negative 16 t squared
velikii [3]

Answer:

\displaystyle a(5)=-32

Explanation:

<u>Instant Acceleration</u>

The kinetic magnitudes are usually related as scalar or vector equations. By doing so, we are assuming the acceleration is constant over time. But when the acceleration is variable, the relations are in the form of calculus equations, specifically using derivatives and/or integrals.

Let f(t) be the distance traveled by an object as a function of the time t. The instant speed v(t) is defined as:

\displaystyle v(t)=\frac{df}{dt}

And the acceleration is

\displaystyle a(t)=\frac{dv}{dt}

Or equivalently

\displaystyle a(t)=\frac{d^2f}{d^2t}

The given height of a projectile is

f(t)=-16t^2 +238t+3

Let's compute the speed

\displaystyle v(t)=-32t+238

And the acceleration

\displaystyle a(t)=-32

It's a constant value regardless of the time t, thus

\boxed{\displaystyle a(5)=-32}

3 0
3 years ago
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