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Naily [24]
3 years ago
10

What volume, in liters, does 128 grams of O2 occupy at STP?

Chemistry
1 answer:
Romashka [77]3 years ago
3 0

Answer: 89.7 L

Explanation:

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Consider the hypothetical reaction 3A + 4B → C + 2D Over an interval of 2.50 s the average rate of change of the concentration o
faust18 [17]

Answer:

Final [B] = 1.665 M

Explanation:

3A + 4B → C + 2D

Average rection rate = 3[A]/Δt = 4[B]/Δt = [C]/Δt = 2[D]/Δt

0.05600 M/s = 4 [B]/ 2.50 s

[B] = 0.035 M (concentration of B consumed)

Final [B] = initial [B] - consumed [B]

Final [B] = 1.700 M - 0.035 M

Final [B] = 1.665 M

3 0
3 years ago
For the skeletal chemical equation BF3(g) + NaH(s) → B2H6(g) + NaF(s) what is the coefficient of B2H6 in the balanced equation?
KonstantinChe [14]

Answer:

Coefficient in front of the B_2H_6  in the balanced equation - 1

Explanation:

The unbalanced Chemical equation is shown below as:-

BF_3+NaH\rightarrow B_2H_6+NaF

On the left hand side,  

There are 1 boron atom and 3 fluorine atoms and 1 sodium and hydrogen atoms.

On the right hand side,  

There are 2 boron atoms and 6 hydrogen atoms and 1 sodium and fluorine atoms.

Thus,  

leftside, BF_3 must be multiplied by 2 to balance boron and right side, NaF must be multiplied by 6 to balance fluorine. Left side, NaH must be multiplied by 6 to balance sodium and hydrogen atoms.

Thus, the balanced reaction is:-

2BF_3+6NaH\rightarrow B_2H_6+6NaF

<u>Coefficient in front of the B_2H_6  in the balanced equation - 1</u>

6 0
3 years ago
Read 2 more answers
The total number of electrons in the outer shell of a sodium atom is?<br>A. 1<br>B.2<br>C.8<br>D.18​
mrs_skeptik [129]

Answer:

1

Explanation:

outershell atoms of an element are also known as valency of that element

so the valency and number of elctron in the outershell of a sodium atom is +1.

hope this will help

mark me as brilliant

7 0
3 years ago
Please review the attachment
astra-53 [7]

Answer: The correct answer is -297 kJ.

Explanation:

To solve this problem, we want to modify each of the equations given to get the equation at the bottom of the photo. To do this, we realize that we need SO2 on the right side of the equation (as a product). This lets us know that we must reverse the first equation. This gives us:

2SO3 —> O2 + 2SO2 (196 kJ)

Remember that we take the opposite of the enthalpy change (reverse the sign) when we reverse the equation.

Now, both equations have double the coefficients that we would like (for example, there is 2S in the second equation when we need only S). This means we should multiply each equation (and their enthalpy changes) by 1/2. This gives us:

SO3 —>1/2O2 + SO2 (98 kJ)

S + 3/2O2 —> SO3 (-395 kJ)

Now, we add the two equations together. Notice that the SO3 in the reactants in the first equation and the SO3 in the products of the second equation cancel. Also note that O2 is present on both sides of the equation, so we must subtract 3/2 - 1/2, giving us a net 1O2 on the left side of the equation.

S + O2 —> SO2

Now, we must add the enthalpies together to get our final answer.

-395 kJ + 98 kJ = -297 kJ

Hope this helps!

8 0
3 years ago
Read 2 more answers
How many electrons does the oxygen atom need to become stable?
NemiM [27]

Answer:

2 electrons

Explanation:

Oxygen has 6 valence electrons and to be stable it needs 8. That means it needs 2 more electrons to have a full octet.

4 0
3 years ago
Read 2 more answers
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