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Yuri [45]
2 years ago
13

At the beach, a student fills two beach pails, one with sand and one with seawater. She places both pails in the same spot in th

e bright sunlight. After several hours, what will the student MOST LIKELY observe?
A.
The sand will be cooler than the seawater.

B.
Both will be the same temperature but cooler than before.

C.
Both will be the same temperature but warmer than before.

D.
The sand will be warmer than the seawater.
Chemistry
2 answers:
Gnesinka [82]2 years ago
7 0

Answer:

Which word in the following sentence is a linking verb?

The gym became noisy when fans stamped and cheered for the home team.

A. became

B. noisy

C. stamped

D. cheered

Which word in the following sentence is a linking verb?

The gym became noisy when fans stamped and cheered for the home team.

A. became

B. noisy

C. stamped

D. cheered

Explanation:

Which word in the following sentence is a linking verb?

The gym became noisy when fans stamped and cheered for the home team.

A. became

B. noisy

C. stamped

D. cheered

Mrrafil [7]2 years ago
6 0

Answer: The answer is D

Explanation:

The answer is D because water moves to much so it take longer to and cool

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All Molecules in a compound are the_____<br> Please Help I don't know the answer.
jonny [76]
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3 years ago
Problem 4
Hunter-Best [27]
<h3>Answer:</h3>

1.93 g

<h3>Explanation:</h3>

<u>We are given;</u>

The chemical equation;

2C₂H₆(g) + 7O₂(g) → 4CO₂(g) + 6H₂O(l) ΔH = -3120 kJ​

We are required to calculate the mass of ethane that would produce 100 kJ of heat.

  • From the equation given;
  • 2 moles of ethane burns to produce 3120 Kilo joules of heat
  • Therefore;

Number of moles that will produce 100 kJ will be;

= (2 × 100 kJ) ÷ 3120 kJ)

= 0.0641 moles

  • But, molar mass of ethane is 30.07 g/mol

Therefore;

Mass of ethane = 0.0641 moles × 30.07 g/mol

                          = 1.927 g

                          = 1.93 g

Thus, the mass of ethane that would produce 100 kJ of heat is 1.93 g

3 0
3 years ago
Determine the value of the equilibrium constant, KgoalKgoalK_goal, for the reaction CO2(g)⇌C(s)+O2(g)CO2(g)⇌C(s)+O2(g), Kgoal=?
NISA [10]

Answer:

The value of the equilibrium constant for reaction asked is 1.24\times 10^{-7}.

Explanation:

CO_2(g)\rightleftharpoons C(s)+O_2(g)

K_{goal}=?

K_{goal}=\frac{[C][O_2]}{[CO_2]}

2CO_2(g)+2H_2O(l)\rightleftharpoons CH_3COOH(l)+2O_2(g)..[1]

K_1=\frac{[CH_3COOH][O_2]^2}{[CO_2]^2[H_2O]^2}

2H_2(g)+O2(g)\rightleftharpoons 2H_2O(l)..[2]

K_2=\frac{[H_2O]^2}{[H_2]^2[O_2]}

CH_3COOH(l)\rightleftharpoons 2C(s)+2H_2(g)+O_2(g)..[3]

K_3=\frac{[C]^2[H_2]^2[O_2]}{[CH_3COOH]}

[1] +  [2] + [3]

2CO_2(g)\rightleftharpoons 2C(s)+2O_2(g)

 ( on adding the equilibrium constant will get multiplied with each other)

K=K_1\times K_2\times K_3

K=5.40\times 10^{-16}\times 1.06\times 10^{10}\times 2.68\times 10^{-9}

K=1.53\times 10^{-14}

K=\frac{[C]^2[O_2]^2}{[CO_2]^2}

On comparing the K and K_{goal}:

K^2=K_{goal}

K_{goal}=\sqrt{K}=\sqrt{1.53\times 10^{-14}}=1.24\times 10^{-7}

The value of the equilibrium constant for reaction asked is 1.24\times 10^{-7}.

4 0
3 years ago
A solution containing aluminium ions forms a white precipitate when a few drops of dilute sodium hydroxide solution are added to
Otrada [13]

Answer:

See explanation

Explanation:

A word equation tries to depict a chemical reaction in words. Letters rather than only chemical formulas are used to show the reaction equation.

Now we want to write a word equation that shows the reaction of sodium hydroxide solution and aluminium sulphate solution:

Alumunium sulphate + sodium hydroxide ------>Aluminium hydroxide + sodium sulphate

7 0
3 years ago
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