Answer:
Because it might be reactive or may lose its property in liquid form..
Answer:
The tension in the string is 78.73 N.
Explanation:
The tension in the string can be determined from the expression;
v = ![\sqrt{\frac{T}{m} }](https://tex.z-dn.net/?f=%5Csqrt%7B%5Cfrac%7BT%7D%7Bm%7D%20%7D)
where: v is the speed of the wave in the sting, T is the tension in the string and m is the mass per unit length of the sting.
Given that: v = 16.2 m/s, and m = 0.3 kg/m.
Then;
16.2 = ![\sqrt{\frac{T}{0.3} }](https://tex.z-dn.net/?f=%5Csqrt%7B%5Cfrac%7BT%7D%7B0.3%7D%20%7D)
Square both sides to have,
= ![\frac{T}{0.3}](https://tex.z-dn.net/?f=%5Cfrac%7BT%7D%7B0.3%7D)
T =
x 0.3
= 252.44 x 0.3
= 78.732
T = 78.732 N
The tension in the string is 78.73 N.
Platinum isotope amu percent abundance
194
195 x 344
Missing 1x76