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inna [77]
2 years ago
13

Two asteroids are located a certain distance away from each other. They have the same mass . The gravitational force of attracti

on is f . If the mass of one of the asteroids is doubled, how will the gravitational force be affected
Physics
1 answer:
m_a_m_a [10]2 years ago
6 0

Answer:

F' = 2F

Explanation:

The gravitational force of attraction between asteroids is given by Newton's Law of Gravitation:

F = \frac{Gm_1m_2}{r^2}

where,

F = Force

G = Universal Gravitational Constant

m₁ = m₂ = m = mass of each asteroid

r = distance between asteroids

Therefore,

F = \frac{Gm^2}{r^2}   --------------------- eq(1)

Now, if we double the mass of one asteroid:

F' = \frac{G(2m^2)}{r^2} \\\\F' = 2\frac{Gm^2}{r^2}

using equation (1):

<u>F' = 2F</u>

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madreJ [45]

Explanation:

a) 7.5= 111.1×2°= 0.1111×2^3

which can also be written as

(1/2+1/4+1/8+1/16)×8

sign of mantissa:=0

Mantissa(9 bits): 111100000

sign of exponent: 0

Exponent(5 bits): 0011

the final for this is:011110000000011

b) -20.25= -10100.01×2^0= -0.1010001×2^5

sign of mantissa: 1

Mantissa(9 bits): 101000100

sign of exponent: 0

Exponent(5 bits): 00101

the final for this is:1101000100000101

c)-1/64= -.000001×2^0= -0.1×2^{-5}

sign of mantissa: 1

Mantissa(9 bits): 100000000

sign of exponent: 0

Exponent(5 bits): 00101

the final for this is:1100000000100101

5 0
2 years ago
A bowling ball has a mass of 5 kg. What happens to its momentum when its speed increases from 1 m/s to 2 m/s?
faltersainse [42]

The linear momentum is given by mv. Here m is mass v is velocity of the body. Given mass and velocities as m=5,v_i=1,v_f=2

Initial momentum is mv_i=5*1=5 and final momentum is mv_f=5*2=10.

The correct answer is (A)

8 0
3 years ago
Please helppp
Y_Kistochka [10]

Answer:

F = 17.3 kN

Explanation:

The normal force must support the weight of the car plus provide for the needed centripetal acceleration.

F = m(g + v²/R ) = 1000(9.8 + 15²/30) = 17,300

6 0
2 years ago
Gravity on Earth is 9.8 m/s2, and gravity on Mars is 3.7 m/s2.
antiseptic1488 [7]
W = mg

Weight on Earth = 50 x 9.8
                          = 490 N

Weight on Mars = 50 x 3.7
                          = 185 N 
8 0
3 years ago
Read 2 more answers
Two objects are moving in the xy-plane. Object A has a mass of 3.2 kg and has a velocity = (2.3 m/s)i+ (4.2 m/s)j and object B h
prisoha [69]

The total momentum of the system is 2.14i + 21.27j.

A vector quantity with both direction and magnitude is momentum. Kg m/s (kilogram meter per second) or N s serve as its units (newton second).

The total starting momentum of a system must match the entire final momentum of the system since momentum is a conserved quantity. The overall momentum does not change.

The total momentum of the system is defined as follows:

As momentum is vector quantity and vectors can be added, so, the momentum of a system is given by

P = Pₓ + P'

where Pₓ is the x-component of momentum

P' is the y-component of the momentum

Also, we know that

P=mv

where m is mass

v is velocity

Thus,

P = Pₓ + P'

P = m₁vₓ + m₂v'

vₓ is the x-component of the velocity

v' is the y- component of the velocity

Given, m₁= 3.2kg

m₂ = 2.9kg

Now,

P = 3.2 (2.3i + 4.2j) + 2.9 (-1.8i +2.7j)

P = (7.36i + 13.44j) + (-5.22i + 7.83j)

P = 2.14i + 21.27j

Thus, the total momentum of the given system is 2.14i + 21.27j.

Learn more about the momentum here:

brainly.com/question/4956182

#SPJ1

8 0
1 year ago
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