Answer:
The number of lines possible for SO2 is 3
Explanation:
The following Procedure should be followed when calculating the number of vibrational modes:-
- Identify if the given molecule is either linear or non-linear
- Calculate the number of atoms present in your molecule
- Place the value of n in the formula and solve.
SO2 is a non-linear molecule because it contains a lone pair which causes the molecule to bent in shape hence, The mathematical formula for calculating the number of non-linear molecule in a infrared region is (3n - 6) here n is the number of atoms in molecule.
hence for Sulphur Dioxide (SO2), n will be 3
<u> Therefore, The number of lines possible for SO2 is (3*3) - 6 = 3</u>
Answer:
Ha is more acidic than Hb because loss of Ha forms a resonance-stabilized conjugate base.
Explanation:
The carbon atom that is next to the carbonyl group in pentan-2-one is known as the alpha carbon atom, this carbon atom bears the Ha, the alpha hydrogen atoms.
Ha is more acidic than Hb because, loss of Ha leads to the formation of a resonance stabilized enolate ion. This resonance stabilization of the ion formed makes loss of Ha an easier process than loss of Hb, hence the answer above.
Answer:
34.3 g NH3
Explanation:
M(H2) = 2*1 = 2 g/mol
M(N2) = 2*14 = 28 g/mol
M(NH3) = 14 + 3*1 = 17 g/mol
23.6 g H2* 1 mol/2 g = 11.8 mol H2
28.3 g N2 * 1 mol/28 g = 1.01 mol N2
3H2 + N2 ------> 2NH3
from reaction 3 mol 1 mol
given 11.8 mol 1.01 mol
We can see that H2 is given in excess, N2 is limiting reactant.
3H2 + N2 ------> 2NH3
from reaction 1 mol 2 mol
given 1.01 mol x
x = 2*1.01/1= 2.02 mol NH3
2.02 mol * 17g/1 mol ≈ 34.3 g NH3
5480milligrams=5.47×10^1grams
5480×10^-2
5.480×10^(-2+3)
5.48×10^1grams
