A student asks the question: "What makes an object move?" Which of the following is the best

Examples of uniform speed

Stella [2.4K]

Answer:

A body is said to be moving with uniform speed, if it covers equal distances in equal intervals of time. ...

6 0

3 years ago

Read 2 more answers

Can someone give me some tips of how to study. I have already tried writing everything in my lesson but it doesn't seem to work

larisa [96]

Highlighter, color coding sections that go together, flash cards, relaxing with someone while they read out questions ( this will help with testing anxiety too). If you get distracted easily use games to study or small sayings instead of the usual white and black sheet of paper.

3 0

3 years ago

A projectile is launched horizontally from the top a 35.2m high cliff and lands a distance of 107.6m from the base of the cliff.

tankabanditka [31]

Answer:

$v_o=40.14\ m/s$

Explanation:

<u>Horizontal Launch </u>

It happens when an object is launched with an angle of zero respect to the horizontal reference. It's characteristics are:

The horizontal speed is constant and equal to the initial speed $v_o$
The vertical speed is zero at launch time, but increases as the object starts to fall
The height of the object gradually decreases until it hits the ground
The horizontal distance where the object lands is called the range

We have the following formulas

$\displaystyle v_x=v_o$

$\displaystyle x=v_o.t$

$\displaystyle v_y=g.t$

$\displaystyle y=\frac{gt^2}{2}$

Where $v_o$ is the initial horizontal speed, $v_y$ is the vertical speed, t is the time, g is the acceleration of gravity, x is the horizontal distance, and y is the height.

If we know the initial height of the object, we can compute the time it takes to hit the ground by using

$\displaystyle y=\frac{gt^2}{2}$

Rearranging and solving for t

$\displaystyle 2y=gt^2$

$\displaystyle t^2=\frac{2\ y}{g}$

$\displaystyle t=\sqrt{\frac{2\ y}{g}}$

We then replace this value in

$\displaystyle x=v_o.t$

To get

$\displaystyle v_o=\frac{x}{t}$

$\displaystyle v_o=\frac{x}{\sqrt{\frac{2y}{g}}}$

$\displaystyle v_o=\sqrt{\frac{g}{2y}}.x$

The initial speed depends on the initial height y=32.5 m, the range x=107.6 m and g=9.8 m/s^2. Computing $v_o$

$\displaystyle v_o=\sqrt{\frac{9.8}{2(35.2)}}\ 107.6$

The launch velocity is

$\boxed{v_o=40.14\ m/s}$

7 0

3 years ago

What property of water allows it to rise up in a plant

Alex

Transpiration is the evaporation of water through leaf stomata. It is the major force moving water through plants. Cohesion and adhesion create tension within xylem that helps move water upward.

5 0

3 years ago

How long will a bus take to travel 150 km at an average speed of 40 km h?

yan [13]

225 mins long will a bus take to travel 150 km at an average speed of 40 km h

Since the average speed is 40km/h it means

40 km can be travelled by it in 1 hour

1 km can be travelled by it in 1/40 hour

So 150km can be travelled by it in 150/40 hours or 225 mins.

By formula time=distance/speed=150/40=3.75hours

Speed = Distance/Time – This tells us how slow or fast an object moves. It describes the distance travelled divided by the time taken to cover the distance. Time = Distance / Speed, as the speed increases the time taken will decrease and vice versa.

To know more about average speed click here

brainly.com/question/4931057

#SPJ4

3 0

1 year ago