Answer:
Explanation:
Given:
For a school event, 1/6 of the athletic field is reserved for the fifth -grade classes and the reserved part of the field is divided equally among the 4 fifth grade classes in the school.
To find: fraction of the whole athletic field reserved for each fifth class
Solution:
Fraction of the whole athletic field reserved for four fifth classes = 
So, fraction of the whole athletic field reserved for each fifth class = 
Answer: b. The waste generated is hazardous and must be disposed of.
c. Nuclear material can be spilled into the ocean if reactors are near the coast.
d. A large amount of cold water is generated, which must be stored somewhere.
Explanation:
The main environmental costs for produced during the nuclear power plant consists of procurement of fuel and the thermal load is also produced with cold water discharge in the sea. This can contaminate the sea, hence, must be stored somewhere. The nuclear waste consists of radioactive substances which are hazardous for the environment. The nuclear based electricity does not produce carbon dioxide.
Attraction between polar molecules
°°The next Lunar Eclipse is on March 23, a Wednesday THIS YEAR - 65 days left!
°° A Lunar Eclipse happens when the moon passes directly behind the earth into its umbra, or, shadow. This can occur only when the sun, Earth and moon are aligned exactly, or very closely so, with the Earth in the middle. Hence, a Lunar Eclipse can occur only the night of a full moon. The type and length of an eclipse depends upon the Moon's location relative to its orbital nodes. Isn't that cool?
↑ ↑ ↑ Hope this helps! :D
Hello!
To solve this problem we are going to use the
Henderson-Hasselbach equation and clear for the molar ratio. Keep in mind that we need the value for Acetic Acid's pKa, which can be found in tables and is
4,76:
![pH=pKa + log ( \frac{[CH_3COONa]}{[CH_3COOH]} )](https://tex.z-dn.net/?f=pH%3DpKa%20%2B%20log%20%28%20%5Cfrac%7B%5BCH_3COONa%5D%7D%7B%5BCH_3COOH%5D%7D%20%29%20)
![\frac{[CH_3COOH]}{[CH_3COONa}= 10^{(pH-pKa)^{-1}}=10^{(4-4,76)^{-1}}=5,75](https://tex.z-dn.net/?f=%20%5Cfrac%7B%5BCH_3COOH%5D%7D%7B%5BCH_3COONa%7D%3D%2010%5E%7B%28pH-pKa%29%5E%7B-1%7D%7D%3D10%5E%7B%284-4%2C76%29%5E%7B-1%7D%7D%3D5%2C75%20)
So, the mole ratio of CH₃COOH to CH₃COONa is
5,75Have a nice day!
