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2 years ago

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Methanol is stored at the temperature of 60degree, the vapor pressure of methanol is 13.2kPa at 20degree and 347kPa at 100degree

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1 answer:

SCORPION-xisa [38]2 years ago

7 0

Answer: im only in 6th grad sory

Explanation:

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Pls answer this one thanks have a great day!!! :)))

Masteriza [31]

Minimumhag is correct.

3 0

2 years ago

5.20763 to three significant figures

Sergio039 [100]

Answer:

5.21

Explanation: You can only have 3 digits, so you would round to the hundredths place

5 0

2 years ago

The coolant in automobiles is often a 50/50 % by volume mixture of ethylene glycol, C2H6O2, and water. At 20°C, the density of e

Misha Larkins [42]

Explanation:

Let the volume of the solution be 100 ml.

As the volume of glycol = 50 = volume of water

Hence, the number of moles of glycol = $\frac{mass}{molar mass}$

= $\frac{density \times volume}{molar mass}$

= $\frac{1.1088 \times 50}{62 g/mol}$

= 0.894 mol

Hence, number of moles of water = $\frac{50 \times 0.998}{18}$

= 2.77

As glycol is dissolved in water.

So, the molality = $0.894 \times \frac{1000}{49.92}$

= 17.9

Therefore, the expected freezing point = $-1.86 \times 17.9$

= $-33.31^{o}C$

Thus, we can conclude that the expected freezing point is $-33.31^{o}C$ .

6 0

2 years ago

A 603.0 g/hr stream of liquid methyl alcohol, also called methanol, (CH3OH) at 8.10 atm and 26.0°C was held at constant pressure

mafiozo [28]

Answer:

$Q=\frac{1385270 J}{hr}$

Explanation:

Methanol's molecular weight: $M=32 g/mol$

Methanol's heat of vaporization: $\Delta H_{vap}=69.69 kJ/mol$

Ideal gas heat capacity (Cp):

$Cp=\frac{5}{2}*R$ where R is the gas constant

$Cp=\frac{5}{2}*8.314 \frac{J}{mol*C}=20.78\frac{J}{mol*C}$

The heat needed to vaporize and bring the gs to 210°C is:

$Q=\frac{603 g/hr}{32 g/mol}*(69690\frac{J}{mol}+20.78\frac{J}{mol*C}*(210-26)C)$

$Q=\frac{1385270 J}{hr}$

4 0

2 years ago

A chemist prepares a solution of barium chloride by measuring out of barium chloride into a volumetric flask and filling the fla

mezya [45]

The given question is incomplete. The complete question is:

A chemist prepares a solution of barium chloride by measuring out 110 g of barium chloride into a 440 ml volumetric flask and filling the flask to the mark with water. Calculate the concentration in mole per liter of the chemist's barium chloride solution. Round your answer to 3 significant digits.

Answer: Concentration of the chemist's barium chloride solution is 1.20 mol/L

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

$Molarity=\frac{n\times }{V_s}$

where,

n = moles of solute

$V_s$ = volume of solution in L

moles of $BaCl_2$ (solute) = $\frac{\text {given mass}}{\text {Molar Mass}}=\frac{110g}{208g/mol}=0.529mol$

Now put all the given values in the formula of molality, we get

$Molality=\frac{0.529\times 1000}{440ml}=1.20mole/L$

Therefore, the molarity of solution is 1.20 mol/L

8 0

3 years ago