The empirical formula is C₂H₆O.
We must calculate the <em>masses of C, H, and O</em> from the masses given.
<em>Mass of C</em> =38.20 g CO₂ × (12.01 g C/44.01 g CO₂) = 10.424 g C
<em>Mass of H</em> = 23.48 g H₂O × (2.016 g H/18.02 g H₂O) = 2.6268 g H
<em>Mass of O</em> = Mass of compound - Mass of C - Mass of H
= (20.00 – 10.424 – 2.6268) g = 6.9487 g
Now, we must <em>convert these masses to moles</em> and <em>find their ratios</em>.
From here on, I like to summarize the calculations in a table.
<u>Element</u> <u>Mass/g</u> <u>Moles</u> <u>Ratio</u> <u>Integers</u>
C 10.424 0.8680 1.999 2
H 2.6268 2.606 6.001 6
O 6.9487 0.4343 1 1
The empirical formula is C₂H₆O.
Answer:
Explanation:
Hello there!
In this case, since this imaginary gas can be modelled as an ideal gas, we can write:
Which can be written in terms of density and molar mass as shown below:
Thus, by computing the pressure in atmospheres, the resulting density would be:
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Answer:Subatomic particle Symbol Relative charge
Proton p +1
Neutron n 0
Electron e- -1
Explanation:
These are the names, symbols, and charges. Hope I helped!
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