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stich3 [128]
3 years ago
10

What does the equation A + BC to B + AC represent

Chemistry
1 answer:
katrin2010 [14]3 years ago
6 0

<em>Displacement reactions</em>

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What is the driving force for the reaction of HCl(aq) and NaOH(aq)?
Andru [333]
HCl and NaOH react based on the following equation:
HCl + NaOH ..............> NaCl + H2O

This reaction is known as a double replacement reaction. In this types of reactions, the electrolyte (and the solvent) is water and the driving force is mainly the formation of a non-electrolyte produce.

Based on this, the driving force in the above neutralization reaction is the formation if the non-electrolyte salt (NaCl)
8 0
3 years ago
if a gas sample has a pressure of 761 mmhg at 0.00°c by how much does the temperature have to decrease to lower the pressure to
Nady [450]
<h3>Answer:</h3>

272.43 K or -0.718°C

<h3>Explanation:</h3>

We are given;

The initial pressure,P1 as 761 mmHg

Initial temperature, T1 as 0.00°C which is equivalent to 273.15 K

Final pressure as 759 mmHg

We are required to calculate the final temperature;

According to pressure law, the pressure of a gas and absolute temperature are directly proportional at constant volume.

That is; Pα T

Therefore, at varying pressure and temperature,

\frac{P1}{T1}=\frac{P2}{T2}

To get final temperature;

T2=\frac{P2T1}{P1}

T2=\frac{(759 mmHg)(273.15K)}{761 mmHg}

T2=272.43K

Therefore, the final temperature will be 272.43 K or -0.718°C

6 0
2 years ago
In the following equation, ______ is being oxidized and ______ is being reduced.
Mashcka [7]

oxidation \: number \: of \: oxygen =  \\ before \: rxn =  - 2 \\ after \: rxn =  - 2

oxidation \: number \: of \: hydrogen = \\ before \: rxn =  + 1 \\ after \: rxn =  \\ 2x - 2 = 0 \\ x =  + 1

oxidation \: number \: of \: carbon =  \\ before \: rxn =  \\ x  - 6 =  - 2 \\ x = 4 \\ after \: rxn =  \\ x - 4 = 0 \\ x = 4

<h2>Option A</h2>

oxidation \: numbers \: remain \: constant \\ so \: none \:a re \: undergoing \: oxidation \: \\ nor \: reduction \:

6 0
1 year ago
Carbon, hydrogen and ethane each burn exothermically in an excess of air. AHⓇ =-393.7 kJ mol. C(s) + O2(g) → CO2(g) H2(g) + % O2
Salsk061 [2.6K]

<u>Answer:</u> The \Delta H^o_{rxn} for the reaction is 51.8 kJ.

<u>Explanation:</u>

Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.

According to this law, the chemical equation is treated as ordinary algebraic expressions and can be added or subtracted to yield the required equation. This means that the enthalpy change of the overall reaction is equal to the sum of the enthalpy changes of the intermediate reactions.

The chemical equation for the reaction of carbon and water follows:

2C(s)+2H_2(g)\rightarrow C_2H_4(g) \Delta H^o_{rxn}=?

The intermediate balanced chemical reaction are:

(1) C(s)+O_2(g)\rightarrow CO_2(g)    \Delta H_1=-393.7kJ    ( × 2)

(2) H_2+\frac{1}{2}O_2(g)\rightarrow H_2O(l)    \Delta H_2=-285.9kJ     ( × 2)

(3) 2C_2H_4(s)+2O_2(g)\rightarrow 2CO_2(g)+2H_2O(l)    \Delta H_3=-1411kJ

The expression for enthalpy of the reaction follows:

\Delta H^o_{rxn}=[2\times \Delta H_1]+[2\times \Delta H_2]+[1\times (-\Delta H_3)]

Putting values in above equation, we get:

\Delta H^o_{rxn}=[(2\times (-393.7))+(2\times (-285.9))+(1\times -(-1411))]=51.8kJ

Hence, the \Delta H^o_{rxn} for the reaction is 51.8 kJ.

6 0
3 years ago
Someone help please this is due today!!?
maria [59]

Answer:

I think beaker three will take longer to boil since there is more water present,compared to the other beakers

3 0
2 years ago
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