Answer: The empirical formula of X is
.
Explanation:
If percentage are given then we are taking total mass is 100 grams.
So, the mass of each element is equal to the percentage given.
Mass of C = 62.4 g
Mass of H = 4.19 g
Mass of O = 33.2 g
Step 1 : convert given masses into moles.
Moles of C=
Moles of H=
Moles of O =
Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.
For C =
For H =
For O =
The ratio of C: H: O = 2.5 : 2 : 1
Converting it into simple whole number ratios by multiplying by 2:
Hence the empirical formula of X is
.
The solubility of carbon dioxide at 400 kPa at room temperature is ;
( B ) 0.61 CO2/L
<u>Given data </u>
pressure of CO₂ = 400 Kpa = 3.95 atm
Kh of CO₂ = 3.3 * 10⁻² mol/L.atm
<h3>Calculate the solubility of carbon dioxide </h3>
Solubility = pressure * Kh value of CO₂
= 3.95 atm * 3.3 * 10⁻² mol / L.atm
= 0.13 mol/l CO₂
= 0.61 CO₂ / L
Hence we can conclude that the solubility of CO₂ at 400 kPa is 0.13 mol/l CO₂.
Learn more about solubility : brainly.com/question/23946616
From the options the closest answer is ( B ) 0.61 CO₂ / L
Mn₂O
Explanation:
The oxide that will most likely form colored solutions is Mn₂O.
This is because most transition metals form colored compounds. Manganese is a transition metal belonging to the d-block on the periodic table.
- Other examples of transition metals are scandium, titanium, iron, copper, cobalt, nickel, zinc
- They belong to the d-block on the periodic table.
- They have variable oxidation states.
- Most of their solutions are always colored.
Learn more:
Periodic table brainly.com/question/8543126
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Answer:
the actual yield is equal to the theoretical yield.
Explanation:
hope this helps